From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3; Optimum moisture content= 18%; Moisture content of soil at the borrow site+ 28%. Specification require that compaction of soil must be at least 95% of the maximum obtained from the proctor test. Compute the maximum compaction expected from the compacted soil using the zero air boids curve for this soil with the following moisture contents: w1= 20%; w2= 25%; w3= 30%.

From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3; Optimum moisture content= 18%; Moisture content of soil at the borrow site+ 28%. Specification require that compaction of soil must be at least 95% of the maximum obtained from the proctor test. Compute the maximum compaction expected from the compacted soil using the zero air boids curve for this soil with the following moisture contents: w1= 20%; w2= 25%; w3= 30%.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.7P

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10. The results of a Standard Proctoretest is tabulated as follows: (SEE PICTURE) Determine the maximum dry unit weight of compaction Determine the optimum moisture content Determine the void ratio at the optimum moisture content Gs = 2.70 Determine the degree of saturation at the optimum moisture content A field unit determination test for the soil, yielded the following data. Moisture content = 12% and moist unit weight = 106 pcf. Determine the relative compaction.
1. (i) A dry soil has a void ratio of 0.65 and its grain specific gravity is = 2.80. What is its unit weight?(ii) Water is added to the sample so that its degree of saturation is 60% without any change in void ratio. Determine the water content and unit weight.(iii) The sample is next placed below water. Determine the true unit weight (not considering buoyancy) if the degree of saturation is 95% and 100% respectively. 2. A sample of saturated soil has a water content of 35%. The specific gravity of solids is 2.65. Determine its void ratio, porosity, saturated unit weight and dry unit weight 3. For a given soil, the void ratio e, water content w, and specific gravity Gs are found to be 0.50, 15%, and 2.65, respectively. Find: (a) Total unit weight of the soil γt (b) Degree of saturation S (c) Dry unit weight γd if the water in the void is removed 4. A shrinkage limit test for a saturated specimen had the initial volume Vi = 21.35 cm3 and initial weight Wi = 37 gf (…
From a standard Proctor laboratory sample of soil Gs= 2.70; maximum dry unit weight = 16.4 kN/m3; Optimum moisture content= 18%; Moisture content of soil at the borrow site+ 28%. Specification require that compaction of soil must be at least 95% of the maximum obtained from the proctor test. Compute the maximum compaction expected from the compacted soil using the zero air boids curve for this soil with the following moisture contents: w1= 20%; w2= 25%; w3= 30%. O a. 94.71% O b. 96.54% O c. 92.07% O d. 90.12%
Determine the maximum dry unit weight of compaction Determine the optimum moisture content Determine the void ratio at the optimum moisture content. Gs = 2.70 Determine the degree of saturation at the optimum moisture content A field unit determination test for the soil, yielded the following data. Moisture content = 12% and moist unit weight = 106 lb/cu.ft. Determine the relative compaction.
The results from a soil compaction test are shown in the table below. The solid grains of the soil have a specific gravity of 2.65. Yary (kN m³) at 2.5% air voids Sample W. m/c(%) (KN/m') Yary (kN/m) 19 12 20.9 3. 16 20.2 4 20 19.7 Which series below gives the dry density at 2.5% air voids (samples 1 to 4) in above table: a. 20.5, 19.2, 17.8, 16.6 O b. 20.2, 19.2, 17.8, 17.0 O. 20.5, 19.2, 17.8, 17.0 O d. 20.5, 19.2, 18.1, 16.6
Q2) A dry sample of soil having the following properties, L.L. = 52%, P.L. = 30%, Gs = 2.7, e = 0.53. Determine the following: 1- dry unit weight ,2-the porosity at plastic limit,
1. A saturated 100 cm³ clay sample has a natural water content of 30%. It is found that the shrinkage limit occurs when the water content is 19%. If the sp. gr. of soil is 2.70.a. Compute the shrinkage ratio.b. Compute the volume of the sample.c. Compute the mass of dry soil sample
A soil sample was compacted.The result of the standard proctor test shows that at 100% compaction, the soil weighs 132.3 pcf with optimum moisture content of 14%. Gs = 2.67 a) What is the saturated unit weight of the soil in pcf? b) What is the maximum dry unit weight of the soil (at zero air voids) in pcf?
Problem 1) A soil sample was compacted. The result of the standard proctor test shows that at 100% compaction, the soil weighs 131.1 pcf with optimum moisture content of 14%. G, = 2.67 a) What is the saturated unit weight of the soil in pcf?
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34 d. 88.41
The Atterberg limits of of a clay soil are liquid limit = 75 %, Plastic limit = 45 % and shrinkage limit = 25 %. If a sample of this soil has a volume of 30 cm³ at the liquid limit and a volume 16.6 cm³ at the shrinkage limit. Determine the specific gravity of solids.
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 95.10 b. 97.25 c. 90.34 d. 88.41