frictionless 1 A =05 B.
Q: 1. A 12 ft ladder weighing 40 lb is place. When a 180 In Man reaches a point 8ftfrom the lower end,…
A: As per the guidelines we will answer the first question for you, for the rest of the question kindly…
Q: e on a 6-in. full journal bearing is 5 intained at 160 °F with N = 300 rị ent of friction and the…
A: GIVEN:r=radius=3inl=length of bearing=1.2×6ns=revolution per sec=30060
Q: x1(t) x2(t) 1 N/m oll At) 1 kg 1 N-s/m 1 kg Frictionless'
A: Write the expression for the equation of motion for the given system.
Q: 4. A 2kg mass rests on a plane inclined at an angle of 32 degrees with the horizontal. What must be…
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Q: If a block is stationary, the friction will always be f = µN, whereu is the coefficient of static…
A: Case - 1: When the block is stationary and no external force is acting on a block, then the friction…
Q: 1) What happens if we neglect friction as the objects move down the inclined plane? Explain. lid 11
A: Kinetic friction acts opposite the object's sliding course. Kinetic friction always opposes the…
Q: The coefficient of kinetic friction is calculated as the ratio of the:
A: F=Friction force N=Normal reaction force μ=Coefficient of friction F=μN It is required to define the…
Q: Find the friction force if coefficient of friction 0.3 and normal force is 120 N
A: Given data : Coefficient of friction=μ Normal force=N To find : Friction force
Q: Given the coefficient of friction for all surfaces A, B, C, and D Is0.30. Neglect friction at the…
A: Given: μ=0.30 WA=20KN WB=15KN WC=15KN WD=10KN
Q: Q2/ As shown in fig.(2). Prove the main equation for the coefficient of frictional force between the…
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Q: 4. Two bodies (A) and (C) of weight (150 N) and (100 N) respectively as shown in figure. the…
A: This question is related to the static equilibrium equations. As we know the impending motion means…
Q: A box is at a horizontal surface with a coefficient of friction of 0.15. Determine the weight of the…
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Q: Q2: Complete the sentences? 1- If the maximum friction force is 100 KN and normal force is 10 KN,…
A: (1) The maximum friction force f=100 KN, and the normal force N=10 kN then the value of friction…
Q: Find the coefficient of friction if friction force is 723N Normal force is 823 N
A: Given data : Normal force=N Friction force=F Required : Coefficient of friction
Q: The coefficient of friction is 0.10 and the pulleys are assumed to be frictionless. 40 kN 60 kN N…
A: To find weight W
Q: A)What force F is needed to get the 300kg block shown in the figure below to move to the right?…
A: There are two types of forces that are acting on a circular surface. One type of force is Radial…
Q: 8 3. Which is the correct Design expression in the case of tension(compression)? (1 Puan) max o, =…
A: Given Data⇒ Design expression Compression Tension
Q: 14. A block shown in Figure is just moved by a force of 200 N. The weight of the block is 600N.…
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Q: Activity 1. In the figure shown, the coefficient of friction is 0.25 for all surfaces of contact.…
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Q: QIA double shoe brake, as shown in Fig. The diameter of the brake drum is 250 mm and the contact…
A: According to the information we have the double shoe brake. The brake drum diameter is 250 mm and…
Q: DRAW F. B. D AND IOWTHE DIRECTION OF FRICTION FORCE
A: GIVEN:
Q: 4. A óm ladder weighs 350 N is placed against a rough vertical wall. The angle between the ladder…
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Q: 3. Which elbow will give the least friction loss? (a) 90° elbow (c) 45° elbow (b) 60° elbow (d) 30°…
A: Need to find which elbow will result in least friction loss
Q: On the ladder resting on the ground and leaning against a smooth vertical wall, the force of…
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Q: Homework Q1/ A pulley is driven by a flat belt running at a speed of 600 m/min. The coefficient of…
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Q: Having the coefficient of frictions (μs = 0.40 and μk = 0.30), Determine whether the block is in…
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Q: is applied on the block as shown in the figure. The magnitude of force of friction (in N) on the…
A: given data; As shown in fig; block of mass 10 kg rests on a horizontal floor acceleration due to…
Q: Q4(a) Explain laws of static friction.
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Q: n a belt arrangement two pulleys are connected by flat belts having same diameters. The maximum…
A: Since the two pulleys are connected by flat belts, therefore, the lap angle is 180 degrees.
Q: Determine the coefficient of static -friction force
A: Given: To determine: Coefficient of static friction
Q: Find the value of coefficient of friction if friction force is 200 N and Normal force is 780 N
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Q: In the figure shown below, the value of co- efficient of dynamic friction between 500 N block and…
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Q: The frictional coefficient has a value of 0.26795, and the normal force is 20kN. Determine the angle…
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Q: 2. Give the procedures in finding the friction factor f using the Moody Chart. Provide…
A: Introduction:-
Q: The coefficint of friction is if A 3.0 kilogram block is sliding down a 25° incline at a constant…
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Q: Find the value of coefficient of friction if friction force 34 N and normal force is 120 N
A: Given data : Friction force=f Normal force=N' Required : Coefficient of friction
Q: The friction force is Directly Pronortional to the normal force
A: Given Data⇒ Friction force
Q: A horse is tied to a horizontal pole using a rope. The rope is only wrapped around the pole without…
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Q: A skier stands on a 5° slope. If the coefficient of static friction is 0.1, does the skier start to…
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Q: Q5. What should be the value of the angle 0 in fig. so that the motion of the 90N block impends down…
A: Draw the free body diagram of the smaller block (consider block 1) having weight of 30 N.
Q: 2. The power transmitted by a belt drive is 2.5 kW. The line ar velocity of the belt is 2.5 m/s. The…
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Q: force P that can be applied horizontally such that A will not move relative to B. Friction is…
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Q: In the given figure, W= 200kg. Assume that the coefficient of friction between surfaces is 0.40.…
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Q: a A crate, which has a weight of W, is placed on an inclination. The force P is applied to prevent…
A: Law of Static equilibrium: A body is said to be in static equilibrium if it satisfies the following…
Q: Q1/ A pulley is driven by a flat belt running at a speed of 600 m/min. The coefficient of friction…
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- A centrifugal clutch has four shoes, each of mass 0·35 kg. When at rest, the radialclearance between the shoes and the clutch drum is 15 mm and the radius to the centre ofgravity of the shoes is 225 mm. The shoes are held on retaining springs of stiffness 10kN/m and the internal diameter of the clutch drum is 600 mm. The coefficient of frictionbetween the drum and the shoes is 0·3.Determine:(a) The speed (in rev/min) at which the clutch starts to engage. For a rotational speed of 1200 rev/min:(b) The force each shoe exerts on the drum. (c) The torque transmitted. (d) The power transmitted.The tensions of a flat belt are;tight side 500N and slack side 180N.the angular speed N and diameter D of the pulley are 280rev/min and 20cm respectively.if the coefficient of friction between the belt and the pulley 0.6 and the mass m of the belt is 1.2kg/m, including centrifugal tension, Determine; (a) initial tension of the belt (b) angle of lap in degrees (C) power transmitted in the kilowatt (D) maximum power attainable in kilowattA small object A is held against the vertical side of the rotating cylinderical container of raidus r due to entrifugal action the coefficient of astatic friction between the object and the container is , determine the expression for the maximum rotational rate co of the container which will keep the object from slipping out the vertical side. Fanpas (Fry: Mos FMS.N Fn-man +N=mrw +N=mYw² {fy.g +4₁ (norw')= ndg
- /A B/ P A homogeneous ring of radius r=0.16 m is suspended from a peg in a vertically downwards uniform gravitational field with g=9.80 m/s?, and loaded by a force P as shown using a ring-fixed massless inextensible chord. The coefficient of static friction between the peg and the ring is u=0.31. If a force P=10.2 N is to be supported without slip at the peg- ring contact, calculate the minimum value of the weight (in N) of the ring (correct to 1 decimal place).A 0.3-kg block is placed against a rotating hollow cylinder of inner radius = 0.7 m. The cylinder rotates around the vertical axis with a constant angular velocity of 15 rad/s. For friction to prevent the mass from sliding down the wall, what is the minimum coefficient of static friction u between the mass and the wall? mThe mass of the flat belt is 0.6kg/m and the tension on the tight side of the belt is 1.7kN the coefficient of friction between the belt and the pulley is 0.2 and the angular speed N of the belt is 400rpm.Angle of lap fita and the diameter D of the pulley 150°and 50cm respectively.with the addition of centrifugal tension Design the belt drive by determine velocity belt centrifugal tension tension on the slack side of the belt power transmitted at this speed in kilowatts maximum power delivered
- Consider a solid cylinder of mass 5 kg and radius 0.3 m on a surface with insufficient friction so that the cylinder will slip (with max friction force). The angle of the incline is 0 = 58 deg, and the coefficient of friction is u = 0.19. If the cylinder starts from rest, calculate the time required for the center of mass to travel a distance of 7 m along the incline. N mgAn engineer is designinga conveyor system for loading haybales into a wagon (Fig.).Each bale is 0.25 m wide, 0.50 mhigh, and 0.80 m long (the dimensionperpendicular to the plane ofthe figure), with mass 30.0 kg. Thecenter of gravity of each bale is atits geometrical center. The coefficientof static friction between abale and the conveyor belt is 0.60, and the belt moves with constantspeed. (a) The angle b of the conveyor is slowly increased. At somecritical angle a bale will tip (if it doesn’t slip first), and at some differentcritical angle it will slip (if it doesn’t tip first). Find the twocritical angles and determine which happens at the smaller angle. (b)Would the outcome of part (a) be different if the coefficient of frictionwere 0.40?The mass of the belt is 0.6kg/m and the tension on the tight side of the belt is 1.7kN.the coefficient of friction between the belt and the pulley is 0.2 and the angular speed N, of the belt is 400rpm.Angle of lap fita and the diameter D of the pulley are 150° and 50cm respectively.with the addition of centrifugal tension, Design the belt drive by determine (A) velocity of the belt (B) centrifugal tension (C) tension on the slack side of the belt (D) power transmitted at this speed in kilowatts (E) maximum
- A block of mass M1 resting on an inclined plane is connected by a string and pulleys to another block of mass M2 as shown in Fig. Find the tension in the string and acceleration of the blocks. Assume the coefficient of friction between the blocks M1 and the plane to be 0.2. M1=1500N , M2=1000N . Angle of inclined glane = 45 degreesHarlgw Cylinder エ:Mg The 65 kg man at right is trapped inside a section of large pipe. If that's not bad enough, the pipe begins to roll, from rest, down a 35 m long, 180 incline! The pipe has a mass of 180 kg and a diameter of 1.2 m. (Assume the man's presence inside the pipe has a negligible effect on the pipe 's rotational inertia.) The coefficient of friction between the pipe and the ground is (0.5, 0.4). -RO Motion Information Free-Body Diagram Event 1: Event 2: 「り t = 2=35m 02 = V2 = 02 = SF a = a2 = (moM) 9 aj = a2 = Mathematical Analysis34 at g sino 4:4F - (mt M) gcoS 2: (m + M)g sino - 'F = (mr M) a zて-Ix two eluntions %3D こ :zC =I« : 'FR = MR*< = MR (4) F = Ma to Sdve for FFL IV-95 Chele tun maxTwo blocks with masses M1 and M2 are connected by a massless string that passes over a pulley as shown. M1 is on an incline of 49.5° with coefficient of kinetic friction μ1 = 0.205. M2 has a mass of 4.84 kg and is on an incline of 35.5° with coefficient of kinetic friction μ2 = 0.105. The pulley can be modeled as a disk with a mass of 305 g and radius of 15 cm. When the system is released, Block M2 accelerates down the incline at rate of 0.52 m/s2. (a) Determine mass of block 1 and the tension forces in the string connecting the blocks and the pulley. Draw accurate free body diagrams of both blocks and pulley, label each force correctly and show the steps in derivation of equations. (b) How much energy will be dissipated by friction 2 second after the blocks are released?