For the titration of 25.0 mL of 0.0100M Sn2+ by 0.0500 M Ti3+ Calculate the potential of solution after the following volumes of Ti3+ have beed added. E0 Sn4+/Sn2+ = 0.139 V, E0 Ti3+/Ti+= 0.77V A) 2.5ml B) 5.0 ml C) 6.0mL
For the titration of 25.0 mL of 0.0100M Sn2+ by 0.0500 M Ti3+ Calculate the potential of solution after the following volumes of Ti3+ have beed added. E0 Sn4+/Sn2+ = 0.139 V, E0 Ti3+/Ti+= 0.77V A) 2.5ml B) 5.0 ml C) 6.0mL
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 54E: Calculate the molar solubility of AgBr in 0.035 M NaBr (KSP=51013).
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For the titration of 25.0 mL of 0.0100M Sn2+ by 0.0500 M Ti3+ Calculate the potential of solution after the following volumes of Ti3+ have beed added.
E0 Sn4+/Sn2+ = 0.139 V, E0 Ti3+/Ti+= 0.77V
A) 2.5ml
B) 5.0 ml
C) 6.0mL
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For the last one, why did you put 0.00025 mole/ 0.00005mole? Isnt the Ti+ at 0.0003?
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