for each voltage-controlled bus if the computed value of generator reactive power exceedsits limits, then the bus type is changed tout ofa. PQ busOb. Slack busuestionO c. No changeO d. PV busNext pageous pageType here to search

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Answered: for each voltage-controlled bus if the…

for each voltage-controlled bus if the computed value of generator reactive power exceeds its limits, then the bus type is changed to a. PQ bus O b. Slack bus Oc. No change O d. PV bus

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter14: Power Distribution

Section: Chapter Questions

Problem 14.17P

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Following figure shows the one-line diagram of a two bus system. Take bus 1 as slack bus, bus 2 as load (PQ) bus. Neglect the shunt charging admittance. Obtain the bus admittance matrixYBUs and find V₂ and 62, power flows and line losses using FDLF method. All the values are given in per unit on 100MVA base. Use a tolerance of 0.001 for power mismatch. 1 Z12= 0.12+10.16 Slack bus V₁ 1.0/0⁰ pu 2 PL2=1.0pu Q12=0.5pu
Equipment ratings for the five-bus power system shown in Figure 7.15 are as follows: Generator G1:Â Â Â Â 50Â MVA,Â 12kV,Â X=0.2 per unit Generator G2: 100Â MVA, 15 kV, X=0.2 per unit Transformer T1: 50 MVA, 10 kV Y/138kVY,X=0.10 per unit Transformer T2: 100 MVA, 15 kV /138kVY,X=0.10 per unit Each 138-kV line: X1=40 A three-phase short circuit occurs at bus 5, where the prefault voltage is 15 kV. Prefault load current is neglected. (a) Draw the positive-sequence reactance diagram in unit on a 100-MVA, 15-kV base in the zone of generator G2. Determine (b) the ThĂ©venin equivalent at the fault, (c) the subtransient fault current in per unit and in kA rms, and (d) contributions to the fault from generator G2 and from transformer T2.
With the same transformer banks as in Problem 3.47, Figure 3.41 shows the oneline diagram of a generator, a step-up transformer bank, a transmission line, a stepown transformer bank, and an impedan load. The generator terminal voltage is 15 kV (line-to-line). (a) Draw the per-phase equivalent circuit, aounting for phase shifts for positive-sequence operation. (b) By choosing the line-to-neutral generator terminal voltage as the reference, determine the magnitudes of the generator current, transmiss ion-line current, load current, and line-to-line load voltage. Also, find the three-phase complex power delivered to the load.
QUESTION 3 The power system network is shown in Figure 3. The magnitude of voltage at bus 1 is adjusted to 12 0° per unit, buses 2 and 3 are the load buses. Line impedances are marked in per-unit on 100 MVA base and the charging susceptances are neglected. Determine the bus voltage at load 2 and 3 using the Gauss-Seidel iteration method (accurate to four decimal places). Perform calculation for two iterations. jo.033 P= 400 Mw HQu= 320 MVar Vi = 120° Figure 3 10.05 +P= 300 MW 70.0125 +QF 270 MVar
A DC Optimal Power Flow problem is to be solved for a 3-bus network. The per-unit reactances of the lines interconnecting the buses are as follows: X12 = 0.25 pu, X13 = 0.15 pu and X23 = 0.2 pu. There is a generator at each bus. The loads at buses 1, 2 and 3 are 125 MW, 300 MW and 100 MW respectively. Bus 1 is taken as the reference bus, and SBase = 100 MVA. Which one of the below is NOT a constraint of the DCOPF problem? Select one: O a. -400 02 - 666.67 03 = P, - 125 O b. None of these C. -500 02 - 1166.67 03 = P3 - 100 d. 900 02 - 500 03 = P2 - 300
1. FIGURE 52 shows the one-line diagram of a simple three-bus power system with generation at bus I. The voltage at bus l is V1 = 1.0L0° per unit. The scheduled loads on buses 2 and 3 are marked on the diagram. Line impedances are marked in per unit on a 100 MVA base. For the purpose of hand calculations, line resistances and line charging susceptances are neglected a) Using Gauss-Seidel method and initial estimates of Va 0)-1.0+)0 and V o)- ( 1.0 +j0, determine V2 and V3. Perform two iterations (b) If after several iterations the bus voltages converge to V20.90-j0.10 pu 0.95-70.05 pu determine the line flows and line losses and the slack bus real and reactive power. 2 400 MW 320 Mvar Slack 0.0125 0.05 300 MW 270 Mvar FIGURE 52
Consider the same 4-bus system shown. Use the tie set method to determine the reliability, unreliability and the expected outage time in hours per year of the system. Assume that the reliability of the generator RG =0.92 and the reliability of each line RL1=RL2 =RL3 RL4=RL5= 0.95. LI L3 ee load RL=0-95 RG = 0 22
b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…
The one-line diagram of a simple power system is shown in Figure below. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. G Stark Item Base MVA Voltage Rating X' x² 20 kV 20 kV 20/220 kV 20/220 kV 100 0.05 0.15 0.15 0.10 0.10 220 kV 0.125 0.125 0.30 0.15 0.25 025 0.7125 0.15 100 100 0.15 0.05 0.10 0.10 0.10 100 0.10 100 100 Lu La 220 kV 0.15 220 kV 0.35 100 A balanced three-phase fault at bus 3 through a fault impedance Zf= jo.I per unit. The magnitude of the fault current in amperes in phase b for this fault is: Select one: A. 345.3 B. 820.1 C. 312500 3888888 产产
Most buses in a typical power-flow program are a.voltage controlled bus b.PQ bus c.PV bus d.Slack bus 2-The power-flow problem is the computation of voltage magnitude and phase angle at each bus in a power system under balanced three-phase steady-state conditions. False True 3-The following sequence currents were recorded in a power system under a fault condition Ipositive=j1.5pu, Inegative=–j0pu, Izero=– j0pu. The fault is a.Three-phase b.Double Line to ground c.Line to ground d.Line to line 4- he following sequence currents were recorded in a power system under a fault condition Ipositive=j1.5pu, Inegative=j0pu, Izero=j0pu. The fault is a.Three-phase b.Double Line to ground c.Line to ground d.Line to line i uploded the houndots (book )here :https://seomidea.com/hct/nu.pdf
A network consisting of a set of generator and load buses is to be modeled with a DC power flow, for the sake of conducting a contingency analysis. The initial flows calculated with the DC power flow give the following information: f°2-4 = - 65.3 MW and fº4-5 = 13.6 MW. The following values of LODF and PTDF factors are given: PTDF54,2-4 = -0.2609, LODF2-4,4-5 = -0.6087. Calculate the contingency flow on line 2-4 due to outage of line 4-5. Select one: O a. -75.5MW O b. None of these O c. -68.85MW O d. -73.58MW O e. 75.5MW O f. -61.75MW
2. The Figure below shows the impedance diagram for a 3-bus system. Using the Gauss- Seidel method, perform 2 iterations to obtain the voltage magnitude and angles at buses 2 and 3. Impedances are given on 100 MVA base. For the first iteration assume V₂[0] = 1.00 ≤ 0° and V3[0] = 1.03 < 0º. Ğ 1 Slack bus 1.02L 0° PV Bus |V3|=1.03 P3=150MW Line 13 13-0.0059+j0.0235 pu Line 12 Z12=0.02 + j0.06 pu Line 23 223 0.0055 +j0.0183 pu Load bus 200MW + 50MVAR ↓ 3