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- Tom enlists the help of his friend John to move his car. They apply forces to the car as shown in the diagram. Here F, = 437 N and F, = 359 N and friction is negligible. In the diagram below, the mass of the car = 3500 kg, e, = -25° and e, = 12°. (Assume the car faces the positive x-axis before the forces are applied.) F, (a) Find the resultant force (in N) exerted on the car. magnitude N direction (counterclockwise from the +x-axis) (b) What is the acceleration (in m/s?) of the car? magnitude m/s² direction (counterclockwise from the +x-axis)Three blocks A, B, and C stand next to each other as shown in the figure. A force F with magnitude 199.4 N is applied to push block C directly and sends the blocks accelerating to the right. Let's assume there is no friction between the blocks and the ground. The mass of A, B, and C are 7, 45, and 94.7 kg, respectively. What is the force applied on block B by block C (in unit of N)? C A TextA 2.00 kg stone is sliding to the right on a frictionless horizontal surface at 5.00 m/s when it is suddenly struck by an object that exerts a large horizontal force on it for a short period of time. The graph in the figure (Figure 1) shows the magnitude of this force as a function of time. Just after the force stops acting, find the magnitude of the stone's velocity if the force acts to the right and find the magnitude of the stone's velocity if the force acts to the left.
- To understand Newton's 3rd law, which states that a physical interaction always generates a pair of forces on the two interacting bodies. In Principia, Newton wrote:To every action there is always opposed an equal reaction: or, the mutual actions of two bodies upon each other are always equal, and directed to contrary parts. (translation by Cajori) The phrase after the colon (often omitted from textbooks) makes it clear that this is a statement about the nature of force. The central idea is that physical interactions (e.g., due to gravity, bodies touching, or electric forces) cause forces to arise between pairs of bodies. Each pairwise interaction produces a pair of opposite forces, one acting on each body. In summary, each physical interaction between two bodies generates a pair of forces. Whatever the physical cause of the interaction, the force on body A from body B is equal in magnitude and opposite in direction to the force on body B from body A.Incidentally, Newton states that…As shown in (Figure 1), block AA (mass 2.10 kgkg) rests on a tabletop. It is connected by a horizontal cord passing over a light, frictionless pulley to a hanging block BB (mass 1.28 kgkg). The coefficient of kinetic friction between block AA and the tabletop is 0.353. The blocks are released then from rest. Find the speed of each block after moving 3.20 cm. Find the tension in the cord.In the figure (Figure 1) a worker lifts a weight w by pulling down on a rope with a force F. The upper pulley is attached to the ceiling by a chain, and the lower pulley is attached to the weight by another chain. The weight is lifted at constant speed. Assume that the rope, pulleys, and chains all have negligible weights. In terms of w, find the tension in the lower chain. In terms of w, find the tension in upper chain. In terms of w, find the magnitude of the force F if the weight is lifted at constant speed.
- Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, this gun accelerates a 6.2-kg projectile from rest to a speed of 3.1 × 103 m/s. The net force accelerating the projectile is 4.8 × 105 N. How much time is required for the projectile to come up to speed?Type your answer here Units Choose your answer hereTom enlists the help of his friend John to move his car. They apply forces to the car as shown in the diagram. Here F, - 431 N and F, = 360 N and friction is negligible. In the diagram below, the mass of the car = 3500 kg, 0, = -25° and 0, - 12°. (Assume the car faces the positive x-axis before the forces are applied.) \0, F, (a) Find the resultant force (in N) exerted on the car. magnitude direction (counterclockwise from the +x-axis) (b) What is the acceleration (in m/s2) of the car? magnitude m/s2 direction (counterclockwise from the +x-axis)A horizontal force, F1 = 55 N, and a force, F2 = 17 N acting at an angle of 0 to the horizontal, are applied to a block of mass m = 3.9 kg. The coefficient of kinetic friction between the block and the surface is uk 0.2. The block is moving to the right. = Randomized Variables F₁ = 55 N F₂=17 N m = 3.9 kg o vi ble. on d ed ed FN=46.72 (b) Solve numerically for the magnitude of acceleration of the block, a in m/s², if 0 = 30°. (a) Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if 0 = 30°. ✓ Correct! a = 15.487 tan() П acos() E 14 sinh() 1 * 1 tanh() cotanh() Degrees O Radians 2 0 VO BACKSPACE sin() cos() cotan() asin() atan() acotan() cosh() Submit Hint . Feedback 7 85 9 6 3 I give up! • DEL HOME ← END y. CLEAR X Hk m 0
- Three stacked blocks have a downward force F' exerted on them as shown: Assume the system is at rest (such as blocks stacked on a stationary table). If m = 6.5 kg and F' = 9.9 N, what is the normal force exerted on the 5m block by the 8m block? Express your answer in N, to at least one digit after the decimal point.A person jumps from the roof of a house 3.7-m high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 m. If the mass of his torso (excluding legs) is 46 kg . Find his velocity just before his feet strike the ground. Express your answer using two significant figures. Enter positive value if the velocity is upward and negative value if the velocity is downward. v= _________ units Find the average force exerted on his torso by his legs during deceleration. Express your answer using two significant figures. Enter positive value if the force is upward and negative value if the force is downward. FTL= ________ unitsGiven a collision in which car #1 of mass 5,000 kg collided with car #2 of mass 2,500kg . If the magnitude of the force of the car #1 on car #2 = 100 N then what is the magnitude of the force of the car #2 on 1 ?