For a certain gene in a diploid organism, eight units ofprotein product are needed for normal function. Eachwild-type allele produces five units.a. If a mutation creates a null allele, do you think thisallele will be recessive or dominant?b. What assumptions need to be made to answer part a?
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For a certain gene in a diploid organism, eight units of
protein product are needed for normal function. Each
wild-type allele produces five units.
a. If a mutation creates a null allele, do you think this
allele will be recessive or dominant?
b. What assumptions need to be made to answer part a?
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- a. How would you synthesize a pentaploid?b. How would you synthesize a triploid of genotypeA/a/a?c. You have just obtained a rare recessive mutation a*in a diploid plant, which Mendelian analysis tells you isA/a*. From this plant, how would you synthesize atetraploid (4n) of genotype A/A/a*/a*?d. How would you synthesize a tetraploid of genotypeA/a/a/a?This pedigree traces the inheritance of a rare disease in humans. a. Based on this pedigree, is the allele for this disease dominant or recessive? Explain. b. What genotypes are possible for the individuals labeled 1, 2, and 3?In 1995, doctors reported a Chinese family in whichretinitis pigmentosa (progressive degeneration of theretina leading to blindness) affected only males. Allsix sons of affected males were affected, but all of thefive daughters of affected males (and all of thechildren of these daughters) were unaffected.a. What is the likelihood that this form of retinitispigmentosa is due to an autosomal mutationshowing complete dominance?b. What other possibilities could explain the inheritance of retinitis pigmentosa in this family? Whichof these possibilities do you think is most likely?
- In a college genetics laboratory course, a healthy student constructs a karyotype from a cell from inside her cheek. She finds only one chromosome 3 and one chromosome 21, plus two unusual chromosomes that do not seem to have matching partners. a. What type of chromosomal abnormality does she have? b. Why doesn’t she have any symptoms? c. Would you expect any of her relatives to have particular medical problems?IN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.Here is a family pedigree for an imprinting disorder caused by a loss of function mutation in a single imprinted gene. After generation I only related individuals are shown. You can assume that the parents not included in the pedigree did not carry the mutation. %3D II IV V Male O Female Affected Carrier a) Does the mutation involve a gene that is normally expressed from the maternal or from the paternal allele? Briefly explain your logic. b) Identify two ways in which the pattern of inheritance shown in the pedigree is different from X-linked inheritance I. Parthenogenesis has been documented in most vertebrate Classes (e.g. birds, fish) but never in mammals. Genomic imprinting provides one explanation for this observation. Why?
- In the accompanying pedigree, the vertical lines stand for protan color blindness, and the horizontal lines stand for deutan color blindness. These are separate conditions causing different misperceptions of colors; each is determined by a separate gene.a. Does the pedigree show any evidence that the genes are linked? b. If there is linkage, does the pedigree show any evidence of crossing over? Explain your answers to parts a and b with the aid of the diagram. c. Can you calculate a value for the recombination between these genes? Is this recombination by independent assortment or by crossing over?(picture added)Retinitis pigmentosa, a form of blindness in man, maybe caused either by a dominant autosomal gene R, or a recessive autosomal gene a. An afflicted man whose parents are both normal marries a woman with genotype AaRr. a. What proportion of the children are expected to suffer from this affliction if R and A are inherited independently? b. If this couple want to have normal children only, what isthe probability of having normal children?You are studying a gene that controls ossicone (horn) length in giraffes. The wild type long-ossicone allele (L) is dominant to the mutant short-ossicone (I) allele. However the L allele is only 60% penetrant. You cross a long-horn heterozygous giraffe to a short- horn giraffe. What phenotypic progeny classes do you expect and at what frequencies?
- A made-up genetic phenotype in humans results in some people having both brown and blond body hair. It is noticeable only if you look closely and these individuals which have small. medium, and large patches of brown hair and small, medium, large patches of blond body hair spread throughout their body. a.) If this phenotype is only seen in females, males have completely blond or brown body hair, how would you describe the genetic nature of this phenotype?A mutation of Drosophila has a wing condition known as beaded. When a beaded fly was crossed with a pure-line normal fly, 53 beaded and 47 normal F1 's were produced. When two of the F, beaded flies were mated, 67 beaded and 33 normal F2's were produced. Explain the genetics of the beaded trait and give the genotypes of all P and F1 generation flies.Galactosemia is a recessive human disease that istreatable by restricting lactose and glucose in the diet.Susan Smithers and her husband are both heterozygous for the galactosemia gene.a. Susan is pregnant with twins. If she hasfraternal (nonidentical) twins, what is theprobability both of the twins will be girls whohave galactosemia?b. If the twins are identical, what is the probabilitythat both will be girls and have galactosemia?For parts (c–g), assume that none of the children isa twin.c. If Susan and her husband have four children, whatis the probability that none of the four will havegalactosemia?d. If the couple has four children, what is the probability that at least one child will have galactosemia?e. If the couple has four children, what is the probability that the first two will have galactosemia andthe second two will not?f. If the couple has three children, what is the probability that two of the children will have galactosemia and one will not, regardless of order?g. If…