following data refers to a 500 hp rolling mill induction motor equipped with a flywheel. No-load speed-40 rpm: Slip at full load 12%: load torque during actual rolling- 41,500 kg-m. Duration of each rolling period-10 seconds. Determine the inertia of the flywheel required in the above case to limit the motor torque to twice its full-load value. Neglect the no-load losses and assume that the rolling mill torque falls to zero between each rolling period. Assume that the motor slip is directly proportional to the torque.
following data refers to a 500 hp rolling mill induction motor equipped with a flywheel. No-load speed-40 rpm: Slip at full load 12%: load torque during actual rolling- 41,500 kg-m. Duration of each rolling period-10 seconds. Determine the inertia of the flywheel required in the above case to limit the motor torque to twice its full-load value. Neglect the no-load losses and assume that the rolling mill torque falls to zero between each rolling period. Assume that the motor slip is directly proportional to the torque.
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following data refers to a 500 hp rolling mill induction motor equipped with a flywheel.
No-load speed-40 rpm: Slip at full load 12%: load torque during actual rolling- 41,500 kg-m. Duration of each rolling period-10 seconds.
Determine the inertia of the flywheel required in the above case to limit the motor
torque to twice its full-load value. Neglect the no-load losses and assume that the rolling mill torque falls to zero between each rolling period. Assume that the motor slip is directly proportional to the torque.
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