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- Set B = { a,b,c,d} and Set C = {b,d,f,g}. Find B U C.Let L = {w = [a, b}*: every a in w is immediately followed by at least one b}.A = [1 1; 1 -1];b = [80; 20]; A_inverse = inv(A);x = A\b; disp('A inverse is');disp(A_inverse);disp(['x1 is ', num2str(x(1)), ' and x2 is ', num2str(x(2))]); if isequal(round(x), [50; 30]) disp('Success');else disp('Incorrect: Please try again');end. Output matlab. .
- f : {1, 2, 3} ® {a, b, c, d} f(1) = c f(2) = b f(3) = a g : {a, b, c, d} ® {x, y, z} g(a) = y g(b) = x g(c) = x g(d) = z Find the composition gofLet A = {a, b, c} and B = {u, v}. Write a. A × B b. B × AFor Letter -> A | B Digit -> 0 | 1 Id -> letter (letter | digit)* Generate NFA and transfer it to DFA.
- Interesting, Intersecting def squares_intersect (s1, s2): An axis-aligned square on the two-dimensional plane can be defined as a tuple (x, y, r) where (x, y) are the coordinates of its bottom left corner and r is the length of the side of the square. Given two squares as tuples (x1, yl, r1) and (x2, y2, r2), this function should determine whether these two squares intersect by having at least one point in common, even if that one point is the shared corner point of two squares placed kitty corner (The intersection of two squares can have zero area, if the intersection consists of parts of the one-dimensional edges.) This function should not contain any loops or list comprehensions of any kind, but should compute the result using only integer comparisons and conditional statements. This problem showcases an idea that comes up with some problems of this nature; it is actually far easier to determine that the two axis-aligned squares do not intersect, and negate that answer! Two squares…Given A={1,2,3,4,56}, B= {2,4,5,6} and C= (1,6,7} 1. B' U C'=∑ = {C,A,G,T}, L = { w : w = CAjGnTmC, m = j + n }. For example, CAGTTC ∈ L; CTAGTC ∉ L because the symbols are not in the order specified by the characteristic function; CAGTT ∉ L because it does not end with C; and CAGGTTC ∉ L because the number of T's do not equal the number of A's plus the number of G's. Prove that L ∉ RLs using the RL pumping theorem.
- Instrument FrequencyCounter to use Stopwatch and StdDraw to make a plot where the x-axis is the number of calls on get() or put() and the y-axis is the total running time, with a point plotted of the cumulative time after each call. Run your program for Tale of Two Cities using SequentialSearchST and again using BinarySearchST and discuss the results. Note : Sharp jumps in the curve may be explained by caching, which is beyond the scope of this question.function [ ] = square_spectrum( L,N )%Activity 1 for CEN415 Summer 2022 x=linspace(0,2*L,200);f1=(-1).^floor(x/L);plot(x,f1)f2=0;for n=1:2:N, f2=f2+4*sin(n*pi.*x/L)/n/pi;endhold onplot(x,f2)hold offend Q1= Run the function for L=3 and N=7 and upload the image of the graph plotted USE MATLAPfunction [ ] = square_spectrum( L,N )%Activity 1 for CEN415 Summer 2022 x=linspace(0,2*L,200);f1=(-1).^floor(x/L);plot(x,f1)f2=0;for n=1:2:N, f2=f2+4*sin(n*pi.*x/L)/n/pi;endhold onplot(x,f2)hold offend Q1= Which one is true? a. When the N increases, the approximated graph tends to be closer to the original square wave b. When the L increases, the approximated graph tends to be closer to the original square wave c. When the L decreases, the approximated graph tends to be closer to the original square wave d. When the N decreases, the approximated graph tends to be closer to the original square wave e. None