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- What is CEMF?a. If you do not go completely around the loop when applying Kirchhoff’s voltage law, then the algebraic sum of the voltages cannot be determined the algebraic sum of the voltages will always be positive the algebraic sum of the voltages will always be negative the algebraic sum is the voltage between the start and finish points b. A p -type semiconductor is a semiconductor doped with impurity atoms whose electron valence is +4 pentavalent impurity atoms trivalent impurity atomsA full-wave bridge rectifier is to be designed to produce a peak output voltage of 10 V, deliver 100 mA to the load, and produce an output with a ripple of not more than 7.5 percent. Assume that the frequency of the source is 50 Hz, and that a constant drop voltage model with Vp = 0.7 V is t of used. D1 D2 vs(1) RL vz(?) D3 D4 Source Rectifier Load a) Calculate the needed value of the load resistor R1. 1 b) Calculate the peak value of the voltage source which should be used V (t). [ c) What will be the value of the ripple voltage V7 [ d) Calculate the value of the required capacitor C. [ e) Explain in your own words the difference between the output with and without using the capacitor in the circuit above.
- Rectifier Circuit. 1. What is V1 reading? a. 110V b. 220V c. 0V d. 146.67V 2. What is V2 reading? 146.67V 207.42V 0V 103.7V 3. What is V3 reading? 132V 104V 207.42V 147V Thank u.Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the aboveIn the circuit below, we have a Zener Diode circuit with a load, RL. Use the same measurements for source voltage V1 and resistor R3 resistance as in the circuit schematic. V1 -15V R3 2700 D1 1N753A RL Determine the lowest possible value for the load RL, so that the voltage drop across it is equal to the Zener voltage. For your diode, use model Zener 1N753A. This diode has a Zener voltage of 6.2V, a Zener current of 60mA, a Zener impedence of 72, and a test current of 20mA.
- liting Q9. For the circuit shown in Figure C9, Calculate the following i) Current through the Silicon diode (Isi). ii) Current through the Resistor R2 (1). iii) Current through the diode D4 (IGe4). iv) Voltage at points V3 and V4. Is D1. D2 Si Si oV4 RI 1.3K2 R3 2.7K R2 3K2 IGe4| 15V D5 Si 03 D4 Ge Ge V2 1V Figure C9Given the zener voltage at 9V and the zener power at 1W, what is the range of allowable values of Iz (operating values). a) 0.11A b) 22mA to 89mA c) 9A d) 0.11A to 9AFAIRCHILD Discrete POWER & Signal Technologies SEMICONDUCTOR ru 1N4001 - 1N4007 Features • Low torward voltage drop. 10 a14 * High aurge eurrent cepablity. 0.160 4.06) DO 41 COLOR BAND DGNOTEs CAT-Cos 1.0 Ampere General Purpose Rectifiers Absolute Maximum Ratings T-26*Cuness atnerwioe rated Symbol Parameter Value Units Average Recttied Current 1.0 375" lead length a TA - 75°C Tsargei Peak Forward Surge Current 8.3 ms single halr-sine-wave Superimposed on rated load JEDEC method) 30 A Pa Total Device Dissipetion 2.5 20 Derste above 25°C Ra Tag Thermal Resistence, Junction to Amblent 5D Storage Temperature Range 55 to +175 -55 to +150 Operating Junetion Temperature PC "These rarings are imithg valuee above whien the serviceatity or any semiconductor device may te impaired. Electrical Characteristics T-20'Cunieas ofherwise roted Parameter Device Units 4001 4002 4003 4004 4005 4006 4007 Peak Repetitive Reverse Vellage Maximum RME votage DC Reverse Voltage Maximum Reverse Current @ rated VR…
- if i want building power supply out 9v. full wave rectifier ,Consists of source 240 voltage 50Hz , resistor and 2 capacitor and 4 dimes and transformer .what is the Equations and circuit diagram for it,and what is Values of componentsPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to c 20:5A L VI-DC20V 220V omsh T 0.01 F 0.02 F 0.0167 F None of the above euerPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V omsh RL VI-DC20V 0.01 F 0.02 F 0.0167 F None of the above