Find the terms a0, a1, a2, a3, and a4 of sequence { an }, where an equals: a. 2n − n2 b. 3n + 1 c. 2n + (−2)n d. 1 – n! e. ⌈n/2⌉ − ⌊n/2⌋
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Find the terms a0, a1, a2, a3, and a4 of sequence { an }, where an equals:
a. 2n − n2
b. 3n + 1
c. 2n + (−2)n
d. 1 – n!
e. ⌈n/2⌉ − ⌊n/2⌋
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- int n = 1; int k - 2; int r = n; if (k < n) { r - ksum = 0; for (int i = 1; i< n; i = sum++ || 2*i)le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"
- hexadecimal We usually write numbers in decimal form (or base 10), meaning numbers are composed using 10 different “digits” {0, 1, . . . , 9}. Sometimes though it is useful to write numbers hexadecimal or base 16. Now there are 16 distinct digits that can be used to form numbers: {0,1,...,9,A,B,C,D,E,F}. So for example, a 3 digit hexadecimal number might be 2B8. (d) How many 3-digit hexadecimals start with a letter (A-F) or end with a numeral (0-9) (or both)? Explain (please answer it the way i can make myself understand)(Numerical) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters to 0, and then generate a large number of pseudorandom integers between 0 and 9. Each time a 0 occurs, increment the variable you have designated as the zero counter; when a 1 occurs, increment the counter variable that’s keeping count of the 1s that occur; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of the time they occurred.Sevens rule, zeros drooldef seven_zero(n):Seven is considered a lucky number in Western cultures, whereas zero is what nobody wants to be. We now bring these two opposites briefly together with positive integers that consist of some solid sequence of sevens, followed by some (possibly empty) solid sequence of zeros. Examples of such integers are 7, 77777, 7700000, 77777700, or 700000000000000. A surprising theorem proves that for any positive integer n, there exist infinitely many integers of such seven-zero form that are divisible by n. This function should return the smallest such seven-zero integer. This exercise is about efficiently generating all numbers of the constrained form of sevens and zeros in strictly ascending order to guarantee finding the smallest working such number. This logic might be best written as a generator to yield such numbers. The body of this generator consists of two nested loops. The outer loop iterates through the number of digits d in the current number.…
- #Solve it with C programing Mr. X is a student of Computer Science. He is facing a problem and needs your help to solve it.The problem is, you will be given N integer numbers( 4<n<=100) which are arranged side by side (x1,x2,x3,x4,.....).Now you have to sort those items in ascending order. After doing this , your job is to print the items in a sorted way and find the median.[NB: when N is odd , Median= (N+1)/2; When N is even Median= (N/2)+1 ] Sample Input: 74 7 11 2 9 3 5Sample Output:2 3 4 5 7 9 115if L1={ab,b} L2={abb,bb} then LIL2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}A1 = {w ∈{0, 1, . . . , 9, .}∗ | w is a valid decimal number Provide regular expression. explain in detail include possible strings and NFA