Find the shear force and bending moment at points C and D.500 lb200 lbAAnswer:Vc = -386 lbfMc = -857 lbf.ftVD = 300 lbfMp = -600 lbf.ftC²6 ft4 ft 4 ftB6 ftD300 lb2 ftE

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Answered: Find the shear force and bending moment…

Find the shear force and bending moment at points C and D. 500 lb 200 lb Answer: Vc = -386 lbf Mc = -857 lbf.ft VD = 300 lbf MD=-600 lbf.ft 6 ft- 4 ft 4 ft B -6 ft- D 300 lb 12 ft E

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.3.2P: Repeat the preceding problem using sx= 5.5 MPa. ??y= 4 MPa. and txy= 3.2 MPa.

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Concept explainers

Combined Loading

Any functioning component, such as machine parts, structural members, pressure vessels, and so on, are all under the influence of more than one force. When anybody is under the influence of more than one force such as shear forces, bending moments, axial forces, torsion, and so on, then such body is said to be under combined loading. A very practical example of combined loading is the crankshaft of an internal combustion engine (IC engine). The crankshaft of the IC engine is under high rpm, which is caused due to the torsional forces. Due to the presence of piston, counterbalances, and internal imbalances, the crankshaft experiences lateral forces and due to the rise in temperature, the crankshaft undergoes thermal expansion, which pulls the crankshaft along the axial direction and lateral direction. The presence of unbalanced loads along the periphery of the crankshaft also induces a bending moment.

Question

Find the shear force and bending moment at points C and D.
500 lb
200 lb
A
Answer:
Vc = -386 lbf
Mc = -857 lbf.ft
VD = 300 lbf
Mp = -600 lbf.ft
C²
6 ft4 ft 4 ft
B
6 ft
D
300 lb
2 ft
E

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