Find the molarity ofNaOH for each trial, theaverage molarity, thestandard deviation, the% RSD, and the pptherror.E19t4647Q b c 6 100%-2=227 2:0*******192022jxAPart A Standardization of NaOHMolarity of HCI (aq) used24Initial Buret Reading for HCFinal Buret Reading for HCI18 Your Average MolarityYour Standard DeviationYour RSDppth errorInitial Buret Reading for NaOHFinal Buret Reading for NaOHvolume HCI usedvolume NaOH usedIf you didn't use this trial put an xmoles of HCI in trialmole of NaOH in trialMolarity of NaOH for trial*227 mass of tartaric acid weighed out=20 volume of flask TA. dissolved into29vol of pipette used for titration3% 4 0 133StandardizationB#10.0225.0124.990.006.216.21xCReport the highlighted data on lab day0.0512 M1.02g100ml25ml#16.2112.536.32XDefaul.... -12 +#2#1325.01 0.0050.00 26.7024.99 26.7023 "just use your 3-4 trials. In the statistics section you will use everyone's25 Part B-Tartaric AcidDMM%0.00128 0.00128 0.001370.000206 0.000202 0.000203#2E#312.53 X19.25X6.72 xmlXF.#14XXXmlX(need 3 good trials)GMB#4 (need 3 good trials)IAHIIf you cale molarity insteps, these guide youJE 23-1-M-A-MA

The molarity (M) is calculated by dividing the moles of solute by the volume of solution in…

Find the molarity of NaOH for each trial, the average molarity, the standard deviation, the % RSD, and the ppth error. E19 t 4 6 Q D G 100%- -2=227 2:0 4 Initial Buret Reading for HC 7 Final Buret Reading for HCI ******* jx A Part A Standardization of NaOH Molarity of HCI (aq) used 22 18 Your Average Molarity 24 Initial Buret Reading for NaOH Final Buret Reading for NaOH 19 Your Standard Deviation 20 Your RSD 21 ppth error 2 volume NaOH used If you didn't use this trial put an x moles of HCI in trial mole of NaOH in trial Molarity of NaOH for trial volume HCI used 27 25 Part B-Tartaric Acid 25 * mass of tartaric acid weighed out 20 volume of flask TA. dissolved into 29 vol of pipette used for titration = 3% 4 0 133 Standardization B #1 0.02 25.01 24.99 0.00 6.21 6.21 x C Report the highlighted data on lab day 0.0512 M 23 "just use your 3-4 trials. In the statistics section you will use everyone's 1.02g 100ml 25ml #1 6.21 12.53 6.32 X Defaul.... -12 + #2 #13 25.01 0.00 50.00 26.70 24.99 26.70 D 0.00128 0.00128 0.00137 0.000206 0.000202 0.000203 M M % #2 E #3 12.53 X 19.25 X 6.72 xml X F. #14 X X Xml X (need 3 good trials) G M B IA #4 (need 3 good trials) HI If you cale molarity in steps, these guide you J E 23-1-M-A- M A

Find the molarity of NaOH for each trial, the average molarity, the standard deviation, the % RSD, and the ppth error. E19 t 4 6 Q D G 100%- -2=227 2:0 4 Initial Buret Reading for HC 7 Final Buret Reading for HCI ******* jx A Part A Standardization of NaOH Molarity of HCI (aq) used 22 18 Your Average Molarity 24 Initial Buret Reading for NaOH Final Buret Reading for NaOH 19 Your Standard Deviation 20 Your RSD 21 ppth error 2 volume NaOH used If you didn't use this trial put an x moles of HCI in trial mole of NaOH in trial Molarity of NaOH for trial volume HCI used 27 25 Part B-Tartaric Acid 25 * mass of tartaric acid weighed out 20 volume of flask TA. dissolved into 29 vol of pipette used for titration = 3% 4 0 133 Standardization B #1 0.02 25.01 24.99 0.00 6.21 6.21 x C Report the highlighted data on lab day 0.0512 M 23 "just use your 3-4 trials. In the statistics section you will use everyone's 1.02g 100ml 25ml #1 6.21 12.53 6.32 X Defaul.... -12 + #2 #13 25.01 0.00 50.00 26.70 24.99 26.70 D 0.00128 0.00128 0.00137 0.000206 0.000202 0.000203 M M % #2 E #3 12.53 X 19.25 X 6.72 xml X F. #14 X X Xml X (need 3 good trials) G M B IA #4 (need 3 good trials) HI If you cale molarity in steps, these guide you J E 23-1-M-A- M A

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.18QAP

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Q3/ A) 0.63 g of a sample containing Na CO,, NaHCO; and inert impurities is titrated with 0.2 M HCI, requiring 17.2 ml. to reach the phenolphthalein end point and a total of 43.5 mL to reach the modified methyl orange end point, How many grams Na CO, and NaHCO, are in the mixture?
TITRIMETRIC DATA SAMPLE: CANE VINEGAR % acidity in label: 4.5% %purity of KHP: 99.80% FORMULA WEIGHT of KHP: 204.22 g/mol STANDARDIZATION OF NaOH SOLUTION TRIAL 1 TRIAL 2 TRIAL 3 Weight of KHP, g 0.1012 0.1004 0.09987 Initial volume of NaOH, mL 5.00 10.01 Final volume of NaOH, mL 4.95 9.99 14.93 Molarity of NaOH Average Molarity of NaOH ANALYSIS OF ACETIC ACID IN A VINEGAR SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of vinegar, mL Initial volume of NaOH, mL 1.00 1.00 1.00 14.98 22.90 30.87 Final volume of NaOH, mL 22.84 30.77 38.75 Molarity of acetic acid Average molarity of acetic acid ANALYSIS OF CARBONIC ACID IN A SODA SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of soda, mL 20.0 20.0 20.0 Initial volume of NaOH, mL 20.20 22.05 23.93 Final volume of NaOH, mL 22.03 23.89 25.8 Molarity of carbonic acid Average molarity of carbonic acid
SCE students measured the concentration of HCl in a solution by titrating with different indicators to find the end point.Indicator Mean HCl concentration (M)(± standard deviation)Number of measurementsBromothymol blue 0.09565 ± 0.00225 28Methyl red 0.08686 ± 0.00098 18Bromocresol green 0.08641 ± 0.00113 29Is the difference between indicators 1 and 2 significant at the 95% confidence level? Answer the same question for indicators 2 and 3
I did an experiment: Molar concentration of Fe (NO3)3=.002 Molar concentration of NaSCN= .002 On my 1st trial: Volume of Fe(NO3)3 = 5 mL Moles of Fe3+, initial (mol) = 1 x 10-5 Volume of NaSCN (mL)= 1 mL Moles of SCN-,initial (mol)= 2 x 10-6 Absorbance was .08 Now trying to find Calculation of Kc I already found [FeNCS2+] equilibrium, from calibration curve (mol/L)= 2.25 x 10-5 Now I need to know: 1. moles FeNCS2+ at equilibrium (10mL) (mol) 2. moles Fe3+, reacted (mol) 3. moles Fe3+, equilibrium (mol) 4. [Fe3+] equilibrium, unreacted, 10 mL (mol/L) 5. moles SCN-, reacted (mol) 6. Moles SCN-, equilibrium (mol) 7. [SCN-] equilibrium (unreacted) 10 mL (mol/L) Feel free to just give me the formula to find these. Or to charge me 2 or 3 questions if I asked too much. Thank you!!!!!!
MAX OF 15 MINUTES A solution contains NaOH (FM = 40), NaHCO3 (FM = 84), and NazCO; (FM = 106), either alone or in a permissible combination. Titration of a 50 mL portion to a phenolphthalein end point requires 16.3 mL of 0.100 M HCI. A second 50.0-mL aliquot requires 38.2 mL of the HCI when titrated to a bromocresol green end point. %3D %3D What is the % w/w composition of the following? Express answers in two decimal places. If the component is not present, write 0.00 in the answer box. NAOH: NazCO3: NaHCO3: 96
Aspirin powder = 0.8110g MW of Aspirin = 180g.mol-1 Volume of 0.5N HCl consumed in back titration = 23.50mL Volume of 0.5N HCl consumed in blank titration = 44.50mL Percent purity (USP/NF) = Aspirin tablets contain NLT 90.0% and NMT 110.0% of the labeled amount of aspirin (C9H8O4) What is the calculated weight (in grams) of pure aspirin?..
Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?
UEid- base tit ration the Consentrat ion of ammonia Solution excess HCL was titrated ith o.07om Na, cO3 Solutian. The volume of Na, Coz Solution reguired was 15.50 ml using the following eguations: 2HCLem> + Na, COgcaps CO2 Cays + HzO1) t NaCL Calculate the concentration (molarity and ppm) of ammonia in the Original Solution.(MM of NHzis 17.031.9/4) 10.0 was by of o.10OMI HCE to Then
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-2 The PPm Concentration of 4.5 *la M Solution off Lif is I1940fやPm D 196. PPm 3 1950 PPm
Part Il: Determination of Standard Solutions mL of 0.200 mL H20 added M Cuso, diluted Tube # M Cuso4-5 H20 added Absorbance about 3 0.200 1.346 3. 4.00 1.00 0.945 4 3.00 2.00 0.715 2.00 3.00 0.469 6. 1.00 4.00 0.281 show calculation for Tube #3 diluted concentration:
The following compounds are available as 0.10 M aqueous solutions: pyridine triethylamine m-nitroaniline NaOH phenol HCIO HCIO4 (рКь = 8.82) (pKb = 3.25) (pKb = 11.53) (K₂ = 1.1 × 10-10) (K₂ = 2.9 × 10-8) Which two solutions could be combined to prepare a pH 6.7 buffer? HCIO and NaOH phenol and NaOH m-nitroaniline and HCIO4 pyridine and HCIO4