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Find the minimum of the function f(x) = x³ – 5x³ – 13x + 4 using quadratic interpolation. Use x0 = 0, x1 = 2, x2 = 4 as an initial quess. Tip: Make table with x0,x1,x2,x3, f (x0),ƒ (x1), f(x2),f(x3). Remove the worst quess from these and arrange 20,x1,x2 values in ascending order then conducts iteration ie. calculate new x3 and f (x3) iterate again until you get two same į values with for example five decimal points. Insert the numerical value of minium value for f(x) here f_x = -30.176 Verify your answer here fi = -30.176

Find the minimum of the function f(x) = x³ – 5x³ – 13x + 4 using quadratic interpolation. Use x0 = 0, x1 = 2, x2 = 4 as an initial quess. Tip: Make table with x0,x1,x2,x3, f (x0),ƒ (x1), f(x2),f(x3). Remove the worst quess from these and arrange 20,x1,x2 values in ascending order then conducts iteration ie. calculate new x3 and f (x3) iterate again until you get two same į values with for example five decimal points. Insert the numerical value of minium value for f(x) here f_x = -30.176 Verify your answer here fi = -30.176

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section: Chapter Questions
Problem 3PT
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Find the minimum of the function f(x) = x³ – 5x³ – 13x + 4 using quadratic interpolation. Use x0 = 0, x1 = 2, x2 = 4 as an initial quess. Tip: Make table with x0,x1,x2,x3, f (x0),ƒ (x1), f(x2),f(x3). Remove the worst quess from these and arrange 20,x1,x2 values in ascending order then conducts iteration ie. calculate new x3 and f (x3) iterate again until you get two same į values with for example five decimal points. Insert the numerical value of minium value for f(x) here f_x = -30.176 Verify your answer here fi = -30.176
Transcribed Image Text:Find the minimum of the function f(x) = x³ – 5x³ – 13x + 4 using quadratic interpolation. Use x0 = 0, x1 = 2, x2 = 4 as an initial quess. Tip: Make table with x0,x1,x2,x3, f (x0),ƒ (x1), f(x2),f(x3). Remove the worst quess from these and arrange 20,x1,x2 values in ascending order then conducts iteration ie. calculate new x3 and f (x3) iterate again until you get two same į values with for example five decimal points. Insert the numerical value of minium value for f(x) here f_x = -30.176 Verify your answer here fi = -30.176
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