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Find the horizontal and vertical asymptotes of the curve. x² + 10 8x²-47x-6 y = Step 1 To find the vertical asymptotes, we look for x-values for which the function becomes infinite. This means for the given function x² +10 8x² - 47x - 6 we should find where the denominator equals 0. - We therefore equate the denominator to 0, and factor. 0 = 8x² 47x6 = (8x + 1)(x-6✔ Solving gives us x = -1/8 X = 1 At x = - -1/8 (smaller value) 6 (larger value). Step 2 Now we evaluate the numerator at these values, to check if it is also 0. -the numerator is 6) Submit Skip (you cannot come back) and at x = 6, the numerator is 8 We therefore conclude that both x = - - and x = 6 are X vertical asymptotes.

Find the horizontal and vertical asymptotes of the curve. x² + 10 8x²-47x-6 y = Step 1 To find the vertical asymptotes, we look for x-values for which the function becomes infinite. This means for the given function x² +10 8x² - 47x - 6 we should find where the denominator equals 0. - We therefore equate the denominator to 0, and factor. 0 = 8x² 47x6 = (8x + 1)(x-6✔ Solving gives us x = -1/8 X = 1 At x = - -1/8 (smaller value) 6 (larger value). Step 2 Now we evaluate the numerator at these values, to check if it is also 0. -the numerator is 6) Submit Skip (you cannot come back) and at x = 6, the numerator is 8 We therefore conclude that both x = - - and x = 6 are X vertical asymptotes.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 39E
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I need help finding the numerator for step 2
Tutorial Exercise Find the horizontal and vertical asymptotes of the curve. x² + 10 8x² - 47x - 6 esc y = Step 1 To find the vertical asymptotes, we look for x-values for which the function becomes infinite. This means for the given function x² + 10 8x² 47x6 we should find where the denominator equals 0. - We therefore equate the denominator to 0, and factor. 0 = 8x²47x6 = (8x + 1)(x - Solving gives us x = -1/8 X x = 6 ✔ At x = - ✔ Step 2 Now we evaluate the numerator at these values, to check if it is also 0. F1 -1/8 (smaller value) Need Help2 6 (larger value). 금 the numerator is We therefore conclude that both x = - Submit Skip (you cannot come back) F2 6) 80 F3 and at x = 6, the numerator is 8 and x = 6 are a F4 16 F5 x. vertical asymptotes. F6 F7
Transcribed Image Text:Tutorial Exercise Find the horizontal and vertical asymptotes of the curve. x² + 10 8x² - 47x - 6 esc y = Step 1 To find the vertical asymptotes, we look for x-values for which the function becomes infinite. This means for the given function x² + 10 8x² 47x6 we should find where the denominator equals 0. - We therefore equate the denominator to 0, and factor. 0 = 8x²47x6 = (8x + 1)(x - Solving gives us x = -1/8 X x = 6 ✔ At x = - ✔ Step 2 Now we evaluate the numerator at these values, to check if it is also 0. F1 -1/8 (smaller value) Need Help2 6 (larger value). 금 the numerator is We therefore conclude that both x = - Submit Skip (you cannot come back) F2 6) 80 F3 and at x = 6, the numerator is 8 and x = 6 are a F4 16 F5 x. vertical asymptotes. F6 F7
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