Find the first partial derivatives of 2х — 4у - f(x, y) = at the point (x, y) = (2,2). 2х + 4y af (2,2) -(2,2) = dx dI (2,2) ду af %3D

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.3: Maxima And Minima
Problem 20E
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Find the first partial derivatives of
2х — 4у
-
f(x, y) =
at the point (x, y) = (2,2).
2х + 4y
af (2,2)
-(2,2) =
dx
dI (2,2)
ду
af
%3D
Transcribed Image Text:Find the first partial derivatives of 2х — 4у - f(x, y) = at the point (x, y) = (2,2). 2х + 4y af (2,2) -(2,2) = dx dI (2,2) ду af %3D
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ISBN:
9780321964038
Author:
GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:
Pearson Addison Wesley,