Find the equation of the line tangent to the graph of f at the indicated value of x. f(x) = 6 + In x; x = 1 ОУ-х-5 ОУ-х+5 O y = x -7 ОУ-х+7

Q: Find an equation of the line tangent to the graph of f(x) = - 2x at (2,- 16).

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Q: Find the slope and the equation of the tangent line to the graph of the function at the given point.…

A: Given,f(x)= -2x +5 and the point (1-,7)

Q: Find the equation of the line tangent to the graph of y = (x3 - 1)(x2 + 1)4 at the point where x =…

A: The Slope of the line at any point is given by the derivative of the function at that particular…

Q: Find an equation of the line tangent to the graph of f(x) when x = 2: f(x) = Vx+2

A: Find the equation of line

Q: Find the slope and the equation of the tangent line to the graph of the function at the given value…

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Q: An equation of the line tangent to the graph of f(x)= x(1-2x) at the point (1,-1) is

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Q: Find the slope m of the line tangent to the graph of the function f(x)=9-x^2 at point P(4,-7).

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Q: Graph f(x) = x +2x -5 and the tangent line to the graph at the point whose x-coordinate is -2.

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Q: Find the equation of the line tangent to the graph of the function at the indicated point. 5) f(x) =…

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Q: Find the slope and an equation of the tangent line to the graph of the function at the specified…

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Q: Find an equation for the line tangent to the graph of 7x f(x) = x + 7 at the point (3, 2.1). y =

A: Given curve is Differentiating with respect to x, we get

Q: Find the derivative of h(x)= (-2x-3)7/ (4x+2)4 You should leave your answer in factored form.

A: To differentiate the given rational function (quotient) in the required (factored) form

Q: Find an equation of the tangent line to the graph of the function at the point (9, 1). y = 2x - 9

A: Concept - used the formula of y-y1 =m(x-x1)  Here m=dy/dx=slope

Q: Find an equation of the tangent line to the graph at the given point. 3(x² + y2}² = 100(x? – y²),…

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Q: The equation of the tangent line to the graph of f(x) = 2x3 − x2 at the point (-1,-3) is

A: We have to find the equation of tangent of the given graph at (-1,-3), we know that slope of the…

Q: Find the equation of the tangent line to the graph of the function f (x) = /4x³ + 5 at the point…

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Q: Find an equation for the line tangent to f(x)=x3 +3x2 -2x-8, at the point where x=1

A: To find the equation of the tangent line at point x = 1 for the given curve.

Q: A3) Find the equation of the line tangent to the graph of f(x) = 5x+7x ---.

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Q: Find an equation of the line that is tangent to the graph of f and parallel to the given line.…

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Q: Find the slope m of the tangent line to the graph of the function at the given point and determine…

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Q: Find the equations of the line that is tangent to f(x) = x3 - x2 +3x - 4 at x = 2

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Q: 1. Find the slope of the line tangent to the graph of the function defined by fix) - 3x - 2x- I at…

A: We’ll answer the 1st question since we answer only one question at a time. Please submit a new…

Q: Find an equation of the tangent line to the graph of y = f(x) when x = 2 if f(2) =-6 and f'(2) =5.

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Q: Find the equation of the tangent line to the graph of x4y16=1 at the point (81,1/3) and at the…

A: We use slope point form to equation of tangent line.

Q: Find the point on the graph of the given function at which the slope of the tangent line is the…

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Q: 1. Find the slope of the line tangent to the graph of the function defined by f(x) = 4 + 2x - x2 at…

A: As you mentioned only 1 solved

Q: Find the equation of the tangent line to the graph of 3x- xy + y - 9 = 0 at the point (2, -3).

A: The graph of 3x3-x2y+y3-9=0 at the point 2,-3

Q: Find the equation of the tangent and normal line of the function f(x)=√2x-1 at the point (5,3)

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Q: 42. At what point on the graph of f(x) = -5x² + 4x – 2 is the slope of the tangent line 6?

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Q: At what points on the graph of f(x) = 2x 3 - 9x 2 - 25x is the slope of the tangent line -1? A) ( ,…

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Q: Find an equation of the tangent line to the graph of the function f(x) = 2x² - 4x +5 at the point…

A: Given, f(x)=2x2-4x+5

Q: Find the slope and equation of the line tangent to f (x) = x2 +9 at the point (1, 10).

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Q: Find equations of the two tangent lines to the graph of f(x) = that pass through the point (-1, -3).…

A: Let the point on the curve c,c2 on the curve through which the tangent line passes, As we know that…

Q: If an equation of the tangent line to the curve y = f(x) at the point x=2 is y=4x-5, find f(2) and…

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Q: Find an equation of the tangent line to the graph at the given point. x2y2 − 9x2 − 4y2 = 0,…

A: Given that, x2y2 - 9x2 - 4y2 = 0 Points are :  (-4, 23) We have to find the tangant line to the…

Q: Find the slope of the line tangent to the curve f(x)=3x-2 when x-2.

A: NOTE: Refresh your page if you can't see any equations. .

Q: Find the slope and the equation of the tangent line to the graph of the function at the given value…

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Q: find the slope and an equation of the tangent line to the graph of the function f at the specified…

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Q: Find the point where the tangent to the graph of f(x)= -x^2-6 is parallel to the line y=4x-1

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Q: Find the slope of the line tangent to the graph of the function at the given value of x. 5/2 y = 9x…

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Q: Find the equation of the line tangent to the graph of f(x)= x2 over (3x-4)3 at the point…

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Q: Find equations of the two tangent lines to the graph of f(x) = x that pass through the point (-1,…

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Q: Find the equation of the line tangent to the graph of f at the indicated value of x. f(x) = 4 +9 In…

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Q: line has a slope of f ' ( x ) = 7x -10 / 11 given that

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Q: Find an equation of the line that is tangent to the graph of fand parallel to the given line.…

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Q: Find the equation of the line tangent to the curve f(x) = 4x² - 6x +39 at x = 1.

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Q: Find an equation of the line tangent to the graph of f(x) = · 1 (2) a) at (1,1); b) at - 3, 27 c) at…

A: To find an equation of the line tangent to the graph:

Q: Find the equation of the line that is perpendicular to the tangent line to f(x) = x4+1 at x = 2 and…

A: Answer and explanation is given below

Q: Find the slope and the equation of the tangent line to the graph of the function at the given value…

A: Topic = Derivative