Find the control limits for a 3-sigma u chart with process average number of nonconformities per inspection unit equaling to 3 and sample size n=3. Select one: a. UCL=36 LCL=18 b. UCL=9 LCL=0 c. UCL=6 LCL=0 d. UCL=18 LCL=0
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Find the control limits for a 3-sigma u chart with process average number of nonconformities per inspection unit equaling to 3 and
Select one:
a.
UCL=36 LCL=18
b.
UCL=9 LCL=0
c.
UCL=6 LCL=0
d.
UCL=18 LCL=0
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- Need help on calculating control limits for x-bar and r-chart based on the samples below: Sample No X-BAR (Sample Mean) R (Sample Range) X-BAR R 1 28.2151942 9.5450186 2 30.5767201 11.1032318 3 29.0253789 5.52221327 4 29.9431791 6.27087883 5 29.947177 12.7568255 6 29.6848334 11.4927456 7 29.2539019 4.72514932 8 29.6694257 13.9330532 9 30.1590205 6.33461804 10 28.6867307 6.49522527 11 30.5960109 8.13717125 12 29.4390565 5.80286433 13 31.863426 3.40227918 14 32.3716448 8.62217828 15 29.7052597 10.0026916 16 30.0060069 4.25003967 17 32.8491753 4.6515662 18 33.5023103 9.62764088 19 28.1876404 9.6980397 20 30.5043768 6.46724539 21 29.6856417 7.65071069 22 32.5728395 9.2483604 23 28.2363719 7.54975234 24 29.6579999 11.3224787 25 28.1319897 13.213391 26 28.8811004 8.08405181 27 31.6730765 12.9865678 28 28.2078142 5.96315947 29 27.9430689 7.39518992 30 29.6269815 9.48802129 31 34.3599108 7.66563648 32 28.2423234 7.34122645…Twenty samples (K=20) of 200 observations (n = 200) were taken by an operator at a workstation in a production process. The number of defective items in each sample was recorded as follows. Sample Number of Defects 1. 12 18 10 4. 15 16 6. 19 7. 17 8 12 11 10 14 11 16 12 15 13 13 14 16 15 18 16 17 17 18 18 20 19 21 20 22 Management wants to develop ap-chart using 3-sigma limits. What is the Lower Control Limit (LCL)? (calculation 2 sig fig)The results of inspection of DNA samples taken over the past 10 days are given below. Sample size is 100. LCLp Day Defectives = 1 5 2 7 3 7 4 9 5 5 6 6 a) The upper and lower 3-sigma control chart limits are: UCL = 0.127 (enter your response as a number between 0 and 1, rounded to three decimal places). (enter your response as a number between 0 and 1, rounded to three decimal places). 7 1 8 6 9 10 10 1
- Factors for Computing Control Chart Limits (3 sigma) Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean x (mm) Range R (mm) 1 156.9 4.2 2 153.2 4.6 3 153.6 4.1 4 155.5 5.0 5 156.6 4.5 Part 4 c) What are the (UCLx) and (LCLx) using 3-sigma? (UCLx) = mm (round your response to two decimal places). (LCLx) = mmThe results of inspection of DNA samples taken over the past 10 days are given below. Sample size is 100. Day 1 2 3 4 5 6 7 8 9 10 Defectives 3 5 5 6 3 3 0 4 6 2 a) The upper and lower 3 3-sigma control chart limits are: UCLp = ___ LCLp =___A control chart for fraction nonconforming is to be established using a center line of p=0.03. What sample size is required if we wish to detect a shift in the process fraction nonconforming to 0.08 with probability 0.50? 1269 475 73 316 216 2 105 150 265
- Management at Webster Chemical Company is concerned as to whether caulking tubes are being properly capped. If a significant proportion of the tubes are not being sealed, Webster is placing its customers in a messy situation. Tubes are packaged in large boxes of 135. Several boxes are inspected, and the following numbers of leaking tubes are found: View an example Sample 1 2 3 Get more help. 4 Tubes 7 7 8 5 1 5 6 7 Calculate p-chart three-sigma control limits to assess whether the capping process is in statistical control. The UCL, equals 1 Sample 8 8 9 10 11 12 13 14 Tubes 7 2 4 8 6 9 MacBook Pro 3 Sample 15 16 17 18 19 20 Total Tubes 8 3 3 5 and the LCL equals (Enter your responses rounded to three decimal places. If your answer for LCL, is negative, enter this value as 0.) 3 6 104 Clear all Check answer O5. The results of inspection of DNA samples taken over the past 10 days are given below. Sample size is 100. Day 1 2 3 4 5 6 7 8 9 10 Defectives 7 9 9 11 7 8 0 11 13 2 a) The upper and lower 3-sigma control chart limits are: Part 2 UCLp = ________ (enter your response as a number between 0 and 1, rounded to three decimal places). LCLp = ________ (enter your response as a number between 0 and 1, rounded to three decimal places).An ?̅ control chart with 3-sigma control limits and subgroup size n = 4 hascontrol limits UCL = 48.75 and LCL = 40.55. Estimate the process standard deviation.
- Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 5 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean (mm) Range R (mm) 158 4.3 151.2 4.4 155.7 4.2 153.5 4.8 156.6 4.5 What is the UCL using 3-sigma?(round your response to two decimal places). 1. 2. 4.The results of inspection of DNA samples taken over the past 10 days are given below. Sample size is 100. Day 1 2 3 4 5 6 7 8 9 10 Defectives 7 9 9 11 7 8 0 11 13 2 The upper and lower 3-sigma control chart limits are: UCLp = (enter your response as a number between 0 and 1, rounded to three decimal places). LCLp = (enter your response as a number between 0 and 1, rounded to three decimal places).An X-bar control chart designed with L=3 and constant sample size "n" has UCL=130.013 and LCL=125.987, if the process is under control and its standard deviation is sigma=1.5, what is the sample size "n"? not enough information 4 6 10 8.
