Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments.y5-1-3-2-11451 5(x, y) =12' 63. The centroid of any triangle is located at the point of intersection of the medians. Recall that a median is a line segment from a vertex to the midpoint of the opposite side. Recall also that the mediansintersect at a point two-thirds of the way from each vertex (along the median) to the opposite side.Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles (from the above information) and using additivity of moments.y2-3-2-113(X, y) =

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Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments. y 2 1 -3 -2 -1 2 3 4 5

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section3.3: Lines

Problem 74E

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Question

Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles and using additivity of moments.
y
5-
1
-3
-2
-1
1
4
5
1 5
(x, y) =
12' 6
3.

The centroid of any triangle is located at the point of intersection of the medians. Recall that a median is a line segment from a vertex to the midpoint of the opposite side. Recall also that the medians
intersect at a point two-thirds of the way from each vertex (along the median) to the opposite side.
Find the centroid of the region shown, not by integration, but by locating the centroids of the rectangles and triangles (from the above information) and using additivity of moments.
y
2
-3
-2
-1
1
3
(X, y) =

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