Find the absolute extrema of the function on the closed interval. f(x) = 3x²+2, [1, 2] (x, y) = minimum maximum (x, y) =

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.3: Maxima And Minima
Problem 8E
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Find the absolute extrema of the function on the closed Interval.
f(x) = 3x²+2,
[1, 2]
(x, y) =
minimum
maximum (x, y) =
Submit Answer
Transcribed Image Text:Find the absolute extrema of the function on the closed Interval. f(x) = 3x²+2, [1, 2] (x, y) = minimum maximum (x, y) = Submit Answer
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Find the absolute extrema of the function on the closed Interval.
f(x) = 3x² + 2,
(x, y) =
minimum
maximum (x, y) =
Submit Answer
[-1, 2]
0,2
2,16
Transcribed Image Text:Find the absolute extrema of the function on the closed Interval. f(x) = 3x² + 2, (x, y) = minimum maximum (x, y) = Submit Answer [-1, 2] 0,2 2,16
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