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- Explain this statement: Although 2-methoxyacetic acid (CH3OCH2COOH)is a stronger acid than acetic acid (CH3COOH), p-methoxybenzoic acid(CH3OC6H4COOH) is a weaker acid than benzoic acid (C6H5COOH).Explain this statement: Although 2-methoxyacetic acid (CH3OCH2COOH) is a stronger acid than acetic acid (CH3COOH), p-methoxybenzoic acid (CH3OC6H4COOH) is a weaker acid than benzoic acid (C6H5COOH).Explain why methyl trifluoroacetate, CF3CO2CH3, is more reactive than methyl acetate, CH3CO2CH3, in nucleophilic acyl substitution reactions.
- Please complete the following question. There is no need to provide an explaination. 20Although codeine occurs in low concentration in the opium poppy, most of the codeine used in medicine is prepared from morphine (the principal component of opium) by the following reaction. Explain why selective methylation occurs at only one OH in morphine to give codeine. Codeine is a less potent and less addictive analgesic than morphine. но. CH,0. [1 кон H [2] CH3I H. CH3 H Ho morphine H. CH3 Ho codeineGive the major organic product(s) of the following reaction. 1) CH3CH2M9B 2) H30+ Give the major organic product(s) of the following reaction. 1) PhMgBr 2) H30+
- PQ-19. Which phosphorus reagent is required for this reaction? (A) PPh3 (B) PPh3 (C) H PPh3 (D) PPh3(b) Cortisone OH H2C CH -HO- H3C Oalcohol O carbon-carbon double bond Oester Oaldehyde Ocarbon-carbon triple bond Oether O amide Ocarboxylate anion Oketone Oamine O carboxylic acid O thiol (c) Prostaglandin PGE2 COOH Но OH Oalcohol O carbon-carbon double bond Oester Oaldehyde Ocarbon-carbon triple bond Oether Oketone O amide O carboxylate anion Oamine Ocarboxylic acid O thiolAnswer the following questions based on the information provided. (a) Sildenafil (Viagra) is used to treat erectile dysfunction (impotence; inability to get or keep an erection) in men. Sildenafil (Revatio) is used to improve the ability to exercise in adults with pulmonary arterial hypertension. One of the key step of Sildenafil synthesis is shown below. OEt O OEt O i) Amine HO CHO ii) H20 washing to remove the HCI residue CI N. i) What's the structure of Amine reagent? Amine structure ii) Why does not carboxyl acid react with amine? iii) Draw the mechanism of the reaction.
