Find equation of (a) the tangent plane to the given surface at the specified point. y = e^x cos (z) , (1, e, 0)
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Find equation of (a) the tangent plane to the given surface at the specified point. y = e^x cos (z) , (1, e, 0)
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- Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.Find an equation of the tangent plane to the given surface at the specified point. = e-, (1, -1, 1)Find equations of the tangent plane and normal line to the surface z + 19 = xe" cos z at the point (19, 0, 0). Tangent Plane: (make the coefficient of z equal to 1). = 0. Normal line: (19, 出) +t( 1).
- 4 Find the equation of the tangent plane and the normal line to the surface z = at the point (-2,0, 3). cos(y)Find parametric equations for the tangent line at the point (cos(), sin(* ), ) on the curve r = cos t, y = sin t, z=t x(t) = y(t)= z(t)= (Your line should be parametrized so that it passes through the given point at t=0).Find an equation of the tangent plane to the given surface at the specified point. Z=e^x-y,(2,2,1)
- Find the second derivative of y with respect to x from the parametric equations given.Find equations of the tangent plane and normal line to the surface z - 4 = xe" cos z at the point (-4, 0, 0). Tangent Plane: (make the coefficient of z equal to 1). = 0. Normal line: (-4, +*001).Find the equation of the tangent plane and the normal line to the given surface at the specified point. 24z + a'y + 8y sin z = 2048 Point: (2, 4, 0) (a) Equation of tangent plane. Be sure to enter an equation. (b) Equation of normal line. You will need to express your answer with symmetric equations but in two parts. (i) Symmetric equations with a and y: (ii) Symmetric equations with a and z:
- Find an equation of the tangent plane to the surface y ln xz2 = 2, at the given point (e, 2, 1) and find a set of symmetric equations for the normal line to the surface at the given point.Show that the curve x = 2 cos(t), y = 3 sin(t) cos(t) has two tangents at (0, 0) and find their equations. y = (smaller slope) y = (larger slope)Find the equation of the tangent line to the curve y = (8 In(x))/x at the points (1, 0) and (e, 8/e). at the point (1, 0) y = at the point (e, 8/e) y = Illustrate by graphing the curve and its tangent lines. y y 5 5 X -1 2 4 -5 -4 -3 -2 1 -5 5 y y 5 5 X -5 -4 -3 -2 F1 1 -1 2 3 4 5 -5 -5 Need Help? Read It