Explain the C++ pseudocode's complexity. e = 2; for (int w = 5; e <= x; w++) { e = e + w; }
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Explain the C++ pseudocode's complexity.
e = 2;
for (int w = 5; e <= x; w++) {
e = e + w;
}
1. Programming is the process of creating a set of instructions that tells a computer how to perform a task.
2. Programs can be written in computer programming languages such as JavaScript, Python, and C++.
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- Explain this C code line per line please #include <stdio.h> #include <malloc.h> void printArray(int**, int); int main() { int i = 0, j = 0, n = 5; int **arr = (int**)malloc(n * sizeof(int*)); for(int i=0;i<n;i++){ *(arr+i) = (int*)malloc(n*sizeof(int)); } for(i=0;i<n;i++){ for(int j=0;j<n;j++){ *(*(arr+i) + j) = 0; } } printArray(arr, n); for(i=0;i<n;i++){ *( *(arr + i) + i) = i+1; } printArray(arr,n); return 0; } void printArray(int ** array, int size) { int i,j; for(i = 0;i<size;i++){ for(j=0;j<size;j++){ printf("%d ", *( *(array + i) + j)); } printf("\n"); } printf("\n"); }In C programing Write a recursive function that returns the product of the digits of its integer input parameter, n. You may assume that n is non-negative. For example, productDigits(243) should return 24, since 2 x 4 x 3 = 24.int productDigits (int n) {Course : Data Structures & Algorithms in C++ Question : Consider the following code: int myFunc(int A[], int n) { int i, j, max = 0; int msis[n]; for ( i = 0; i < n; i++ ) msis[i] = A[i]; for ( i = 1; i < n; i++ ) for ( j = 0; j < i; j++ ) if (A[i] > A[j] && msis[i] < msis[j] + A[i]) msis[i] = msis[j] + A[i]; for ( i = 0; i < n; i++ ) if ( max < msis[i] ) max = msis[i]; return max; }a) What is the time complexity of the algorithm?
- Code in C + In this lab we will be reinforcing our understanding of a number of concepts in C...arrays, struct, conditions, loops and loop controls - Allow the user to enter multiple pairs of x and y coordinates on a 2 dimensional graph (these numbers may be considered unitless) along with a text label for that set of points. You must use a "struct" data type to define how these are stored. - The x and y coordinates should be type "float" or "double" - Allow multiple data points to be entered by the user, so the first thing the user must ask is how many coordinates will be entered. Since multiple entries will be made you must create an array of that "struct" type. - Once all of the coordinates and labels are entered, calculate the distance between each set of points (you DO NOT have to store all of the distances!!!). In this lab you may use "math.h" (it may be useful). - Determine which coordinates are closest to each other out of all of the pairs. - Determine which coordinates are…C++ PROGRAMMING PART C Please help me i am stressing so much on this. I would really appreciate it. THIS was the code provided to me to help me solve the question. const int N =31; // N parking spaces bool parking[N]; // the garage void EmptyTheLot(bool parking[], int N) { for(int i=0; i<N; i++) p[i]=false; // empty space } // returns -1 if no space found, //otherwise it returns 0<=i<N for a valid space. int FindSpace(int PlateNumber, bool parking[], int N) { // ????? } main() { EmptyTheLot(parking, N); // start with an empty parking garage. // get plate numbers and fill lot. }For the C code int dw_loop(long x) { long y = x* x; long 'p - &x; long n - 2*x do { x += y; (*p)++; n--; } while (n > 0); return x; }
- 1- What is the ouput of the following C code segment? void * T( void* me) { int s=03; for (int k=1; k<=me; k++) S = s +k; printf("%d",s); main() { pthread_t tids[4]; for ( int i=1; i<=4;i++) pthread_create(&tids[i],NULL,T,void* i ); a) 11 11 b) 23 4 5 in any order 13 6 10 in any order d) O 1 2 3 4 in any order Boş bırakExplain this c code in details. #include <stdio.h> int main() { int max_weight_truck, n; scanf("%d", &max_weight_truck); scanf("%d", &n); int weight_item[n]; int priority[n]; int p_sort[n]; int w_sort[n]; int a[n]; for(int i=0; i<n; i++) scanf("%d", &weight_item[i]); for(int i=0; i<n; i++) scanf("%d", &priority[i]); //sorting priority array for(int i=0; i<n; i++) p_sort[i]= priority[i]; int temp=0; for (int i = 0; i < n; i++) { for (int j = i+1; j < n; j++) { if(p_sort[i] < p_sort[j]) { temp = p_sort[i]; p_sort[i] = p_sort[j]; p_sort[j] = temp; } } } for(int i=0; i<n; i++) a[i]= 0; for(int i=0; i<n; i++) { int index; for(int j=0; i<n; j++) { if(p_sort[i]== priority[j] && a[j]==0) { index= j; break; } } w_sort[i]= weight_item[index]; a[index]=1; } int s=0, i=0,j=0,truck=5, l=0; int o_item[truck], unused_space[truck]; // initializing arrays for(i=0; i<truck; i++) { o_item[i]= 0; unused_space[i]= 0; } i=0; while(truck>0)…Write a c++ recursive function that takes two integers n and k, and prints all binary strings that contains k number of ones and n is the total number of digits. Example, if n = 3 and k = 2, the following strings will be printed: 011, 101, 110 Need complete code and output screenshot
- 1. In C++, Displaying the elements of array using while loop?Explain this c++ statement void bar(int* panam) {*panam +=1;}PROGRAMMING LANGUAGE: C++ // vectors: overloading operators example#include <iostream>using namespace std;class counter{private:int count;public:counter():count(0){}counter(int c):count(c) {} int get_count(){return count;} counter operator++ (int){return counter(count++); } counter operator-- (int){return counter(count--);}};int main(){counter c1, c2, c3;c1++;c2--;cout<<'\n'<<c1.get_count();cout<<'\n'<<c2.get_count();cout<<endl;c3 = c1++;cout<<'\n'<<c1.get_count();cout<<'\n'<<c3.get_count();getch();return 0;} Go through the above code and write the output of the given code segment. counter c1(5), c2(10), c3;c3=c1++;c2=--c3;;cout<<”\n”<<c1.get_count();cout<<”\n”<<c2.get_count();cout<<”\n”<<c3.get_count();