Experiment 11: ACID-BASE TITRATION Sample Data Collection and Results Pages Volume of NaOH used in the Titration: Rough trial Trial 3 Trial 1 Trial 2 Initial reading (mL) o.00mL Z1.0SmL O .0om o.00ML Final reading (mL) 43.15 mL Z1.50mL 21.6om L z1.45ML Volume dispensed (mL) 21.55ML ZI. L5mL 21.5OML 21.o0OmL 21.6omL Average volume of NaOH used (Trials 1-3) O. 2012 M Molarity of NaOH MOLES MOLARITY = Unknown Vinegar #_N A LITERS Calculation of moles HC2H3O2 in 5.00 mL vinegar: acetie acid =21. o om Ha0H Moles of
Experiment 11: ACID-BASE TITRATION Sample Data Collection and Results Pages Volume of NaOH used in the Titration: Rough trial Trial 3 Trial 1 Trial 2 Initial reading (mL) o.00mL Z1.0SmL O .0om o.00ML Final reading (mL) 43.15 mL Z1.50mL 21.6om L z1.45ML Volume dispensed (mL) 21.55ML ZI. L5mL 21.5OML 21.o0OmL 21.6omL Average volume of NaOH used (Trials 1-3) O. 2012 M Molarity of NaOH MOLES MOLARITY = Unknown Vinegar #_N A LITERS Calculation of moles HC2H3O2 in 5.00 mL vinegar: acetie acid =21. o om Ha0H Moles of
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.22QAP
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With the attached data, how do o calculate the molarity of vinegar?
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