Step 1 (Quesfion Step 2 Step 3 Fisst coente and lebels. Node a) a Ciacuit diagpam with the elemeuts Vs = Va 6) CCXLSR+Rt LS LS v6) solurion!- Vs = Va@) LRS+R+Ls Amlying kelt Node @ Souote WHoge inteming amut zsutgaingameut VsXL = Va(4) - vas) + va($)-0 VeX L Vals) = pagallel Conmeetion f capacitor and indluctod Yes Vs - sva (s) Above Ele toical ciocuit Converted into S-domain x + vae) RLC we Know that Vs - sva(s) L.T Va@2 = RS s+ tet ac LS LOT LC L Vs Yes RS RS Va(s) = Vs RS LT Laplece toans fom vs/RC s4 5/Re +%c Vs est+ V (s)= Va) = %3D +> Load vOltage RS Step 4 Step 5 Step 6 VL 6) = Vs 1R C LS Vt)- vsē Sin Vs/RC 29b=5/Rc Re te 246=1/RC 26=R Vs X 2RC vs/RC R C Vs Ic II ($)= ZRC RLCS (s4$/RC+) time VSIRC Because domain Output or toad side voitage L (S)= 2 we Kn Cerbseu I.LT y Sinat TRicing invease laplece bensfom す Vs RC e Sin Vs xe RC

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Can someone help me explain the DIAGRAM / EVERY STEP, how and why with regards to the solution and also the laplace transformation.

Step 1
(Quesfion
Step 2
Step 3
Fisst coente
and lebels.
Node a)
a Ciacuit diagpam with the elemeuts
Vs
= Va 6)
CCXLSR+Rt LS
LS v6)
solurion!-
Vs = Va@) LRS+R+Ls
Amlying
kelt Node @
Souote
WHoge
inteming amut zsutgaingameut
VsXL = Va(4)
- vas)
+ va($)-0
VeX L
Vals) =
pagallel
Conmeetion f
capacitor and
indluctod
Yes
Vs - sva (s)
Above Ele toical ciocuit
Converted into S-domain
x + vae)
RLC
we Know that
Vs - sva(s)
L.T
Va@2 =
RS
s+ tet ac
LS
LOT
LC
L
Vs
Yes
RS
RS
Va(s) =
Vs
RS
LT Laplece toans fom
vs/RC
s4 5/Re +%c
Vs
est+
V (s)= Va) =
%3D
+> Load vOltage
RS
Transcribed Image Text:Step 1 (Quesfion Step 2 Step 3 Fisst coente and lebels. Node a) a Ciacuit diagpam with the elemeuts Vs = Va 6) CCXLSR+Rt LS LS v6) solurion!- Vs = Va@) LRS+R+Ls Amlying kelt Node @ Souote WHoge inteming amut zsutgaingameut VsXL = Va(4) - vas) + va($)-0 VeX L Vals) = pagallel Conmeetion f capacitor and indluctod Yes Vs - sva (s) Above Ele toical ciocuit Converted into S-domain x + vae) RLC we Know that Vs - sva(s) L.T Va@2 = RS s+ tet ac LS LOT LC L Vs Yes RS RS Va(s) = Vs RS LT Laplece toans fom vs/RC s4 5/Re +%c Vs est+ V (s)= Va) = %3D +> Load vOltage RS
Step 4
Step 5
Step 6
VL 6) =
Vs 1R C
LS
Vt)- vsē
Sin
Vs/RC
29b=5/Rc
Re
te
246=1/RC
26=R
Vs X
2RC
vs/RC
R C
Vs
Ic
II ($)=
ZRC
RLCS (s4$/RC+)
time
VSIRC
Because
domain
Output or
toad side
voitage
L (S)=
2
we Kn
Cerbseu
I.LT y Sinat
TRicing invease laplece bensfom
す
Vs
RC
e
Sin
Vs xe
RC
Transcribed Image Text:Step 4 Step 5 Step 6 VL 6) = Vs 1R C LS Vt)- vsē Sin Vs/RC 29b=5/Rc Re te 246=1/RC 26=R Vs X 2RC vs/RC R C Vs Ic II ($)= ZRC RLCS (s4$/RC+) time VSIRC Because domain Output or toad side voitage L (S)= 2 we Kn Cerbseu I.LT y Sinat TRicing invease laplece bensfom す Vs RC e Sin Vs xe RC
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