Eddie's Precision Machine Shop is insured for $700,000. The present yearly insurance premium is $1.00 per $100 of coverage. A sprinkler system with an estimated life of 20 years and no salvage value can be installed for $20,000. Annual maintenance costs for the sprinkler system are $1,800. If the sprinkler system is installed, the system must be included in the shop's value for insurance purposes, but the insurance premium will reduce to $0.40 per $100 of coverage. Eddie uses a MARR of 15 %/year. Click here to access the TVM Factor Table Calculator

ENGR.ECONOMIC ANALYSIS
14th Edition
ISBN:9780190931919
Author:NEWNAN
Publisher:NEWNAN
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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Eddie's Precision Machine Shop is insured for
$700,000. The present yearly insurance
premium is $1.00 per $100 of coverage. A
sprinkler system with an estimated life of 20
years and no salvage value can be installed for
$20,000. Annual maintenance costs for the
sprinkler system are $1,800. If the sprinkler
system is installed, the system must be
included in the shop's value for insurance
purposes, but the insurance premium will
reduce to $0.40 per $100 of coverage. Eddie
uses a MARR of 15 %/year.
Click here to access the TVM Factor Table
Calculator
Part a
What is the annual worth of this
investment? $
Carry all interim calculations to 5
decimal places and then round your
final answer to the nearest dollar. The
tolerance is ±5.
Transcribed Image Text:Eddie's Precision Machine Shop is insured for $700,000. The present yearly insurance premium is $1.00 per $100 of coverage. A sprinkler system with an estimated life of 20 years and no salvage value can be installed for $20,000. Annual maintenance costs for the sprinkler system are $1,800. If the sprinkler system is installed, the system must be included in the shop's value for insurance purposes, but the insurance premium will reduce to $0.40 per $100 of coverage. Eddie uses a MARR of 15 %/year. Click here to access the TVM Factor Table Calculator Part a What is the annual worth of this investment? $ Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is ±5.
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