FigureyF₁X0mg2F2HN1 of 1Part EWhat is the velocity of the box after 15 s?Express your answer to three significant figures with appropriate units.► View Available Hint(s)μAValueSubmitProvide FeedbackUnits? Learning Goal:To use the principle of linear impulse todetermine the change in velocity of a boxsubject to multiple forces.The block shown in (Figure 1) has mass m =40 kg and is subjected to forces F₁ = 230 Nat an angle = 20° below the horizontaland F2 = 70 N. The coefficient of kineticfriction between the box and the surface isk=0.11. What is the velocity of the boxafter 15 s if it starts at rest?FigureF₁0mgNF2₂HN1 of 1What is the magnitude of the normal force between the box and the ground?Express your answer to three significant figures with appropriate units.►View Available Hint(s)N =SubmitPart BI₁ =Part CWhat is the impulse in the horizontal direction due to F₁ ?Express your answer to three significant figures with appropriate units.► View Available Hint(s)SubmitValueI2 =Part DμÃSubmitIfr =μAValueWhat is the impulse in the horizontal direction due to F2?Express your answer to three significant figures with appropriate units.► View Available Hint(s)SubmitValueμAUnitsHAUnitsWhat is the impulse in the horizontal direction due to friction?Express your answer to three significant figures with appropriate units.►View Available Hint(s)Value?UnitsUnits?Review

Answered: Image /qna-images/answer/30674209-2c26-4341-a3fe-105e0ece5817.jpg

earning Goal: use the principle of linear impulse to etermine the change in velocity of a box ubject to multiple forces. ne block shown in (Figure 1) has mass m = 0 kg and is subjected to forces F₁ = 230 N an angle = 20° below the horizontal nd F270 N. The coefficient of kinetic ction between the box and the surface is 0.11. What is the velocity of the box ter 15 s if it starts at rest? What is the magnitude of Express your answer to ▸ View Available Hint(s N = Submit Part B HA Value What is the impulse in the Express your answer to ▸ View Available Hint(s μA

earning Goal: use the principle of linear impulse to etermine the change in velocity of a box ubject to multiple forces. ne block shown in (Figure 1) has mass m = 0 kg and is subjected to forces F₁ = 230 N an angle = 20° below the horizontal nd F270 N. The coefficient of kinetic ction between the box and the surface is 0.11. What is the velocity of the box ter 15 s if it starts at rest? What is the magnitude of Express your answer to ▸ View Available Hint(s N = Submit Part B HA Value What is the impulse in the Express your answer to ▸ View Available Hint(s μA

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q3: Three forces are acting on a steel plate with 4m length by 4m width shown in figure. These three forces are required to cause a horizontal resultant acting through point A. If F = 405N, %3D 1) The value of horizontal resultant R is: E D P. B.
Q4: By using the transformations of a couple, replace the two couples shown in the figure by one couple with the forces acting horizontally at A and B. (Ans. FA = FB = 33.333 N) %3D 100 N 100 N 2.5 m 3 4 1.5 m B - 1m - 200 N 200 N
The initially stationary 15-kg block is subjected to the time-varying force whose magnitude P is shown in the plot. The 40° angle remains constant. Determine the block speed at (a) t = 1.9 s and (b) t = 4.5 s. 122 15 kg 40 S4 = 0.51 H = 0.41 5.4 Answers: (a) At t = 1.9 s, v= m/s (b) At t = 4.5 s, v= i m/s
The 300-N block in the figure is at rest on the rough horizontal plane before the force P is applied at t = 0. The magnitude of P is 80t N, where t is the time in seconds, and its direction is constant. The coefficients of static and kinetic friction are µ̟ = 0.40 and µk = 0.20, respectively. Which of the following most nearly gives velocity of the block after 5 seconds? 300 N P = 80t N
ㅈ PROBLEM S The beam shown has Young's modulus E and moment of inertia I. The end X= O by the angle to as shown. 50 cm A E 香 ← 5.1) What are the boundary conditions at x=0, x=L? 5.2) Solve for the vertical beam deflection U/*). Your answer should be in terms of E, I, do, x, L. 5.3) Find the reactions at the fixed end x=0. PROBLEM 6 10cm fixed. The and X-L is rotated is x=L B for →x 30cm C > M дека т L at A, The horizontal team ABC is supported by pin a and the vertical member at B. All connections are plus. All members have a 1x1 cm² square cross section. The Young's modulus is 7061a. The structure is loaded by the moment M at C as shown. 6.1) What is the bending moment of mertia of the vertical member at B 6,2) Find the critical value of M for buckling failure, which member is likely to buckle? 6
A beam supported by three identical springs at points A,B,C (see figure). Given that flexural of rigidity of the beam, EI= 2.029X1011 N.mm2 ; spring constant,k = 1471.5N/mm, w=116N/mm All dimensions are in mm. 1. What is the reaction for at point A,B and C? 2. What is the deflection at point B? 3. Please draw shear-force and bending moment diagram.
The continuous beam shown in the figure is fixed at both ends A and D, and supported by rollers at B and C. Assume I 800 x 106 mm and E = 70,000 MPa. %3D W1 BO C 8m 8 m 4 m 4 m W1 (kN/m) F (kN) s (mm) 20 60 25 If there is a settlement of S at the support C, solve the following using slope deflection method: 3. Reaction at A, RA in kN. 4. Moment at A, MA in kN-m 5. Reaction at D, RD in kN 6. Moment at D, MD in kN-m
× QUESTION 1: Slope-Deflection Method Determine the reactions and draw the shear and bending moment diagrams for the frame shown in Figure Q1 for the loading shown. Use the slope deflection method. 10 KN 1 A 12 KN- -1.5 m. > ☺ T +27 78 816 5248 B 24 kN/m Add a caption... m Figure 01 T O 1.5 m Swipe up for filters 1.5 m ୮ (1
Q3: Three forces are acting on a steel plate with 4m length by 4m width shown in figure. These three forces are required to cause a horizontal resultant acting through point A. If F = 405N, %3D 1) The value of horizontal resultant R is: A.
3. A civil engineering structure of mass m= 5000kg and stiffness k = 720 kN/m is excited by a square pulse of force shown in Figure Q.3. force 2 kN time 0.2 s Figure Q.3. (a) Using Duhamel's integral determine the displacement and velocity of the mass at the end of pulse. Note; the undamped impulse is given by: h(t)=sin (ot). ma, (b) Then using the following equation for free vibration find the displacement of the mass at t= 04 s: x(1) = Asin (», (t-02)) + Bcos(@,(1-02))
At the instant shown, the slider D has a velocity of 3 ft/s up the channel and its speed is decreasing at a rate of 0.5 ft/s². Determine at this instant: a. The angular accelerations a and acp (include magnitude and direction) b. The acceleration of point C in Cartesian form. Solve the problem using any method. 3.a a AB acD 3.b ac = = 10 in. 8 in. A B 12 in. D 30°
Beam AC is in equilibrium with loading 100 N at B shown in the figure when β = 45. Determine the unknown forces Ax and Ay at A in x and y direction and Rc perpendicular to the beam AC in y’ direction at C by using the equilibrium equations: ∑ ???= 0 ; ∑ ??y= 0; and ∑ ???= 0 where o is an arbitrary point. (you have three equations to solve three unknowns)