e enthalpy of Vaporizatio of a liquid is 14.4 KJ at 180K, its boiling point at 1 bar. The molar volumes quid and the vapor at the boiling point are 115 cm³mol-¹ and 14.5 liter mol-1, respectively. a. Use the Clapeyron equation to estimate dP/T at the boiling point. b. Now use the Clausius-Clapeyron equation to calculate dP/T at the boiling point. C. What is the percent error in P/T when using the Clausius-Clapeyron equation? dP dT d. What approximations in the derivation of the Clausius-Clapeyron equation lead to the error in
e enthalpy of Vaporizatio of a liquid is 14.4 KJ at 180K, its boiling point at 1 bar. The molar volumes quid and the vapor at the boiling point are 115 cm³mol-¹ and 14.5 liter mol-1, respectively. a. Use the Clapeyron equation to estimate dP/T at the boiling point. b. Now use the Clausius-Clapeyron equation to calculate dP/T at the boiling point. C. What is the percent error in P/T when using the Clausius-Clapeyron equation? dP dT d. What approximations in the derivation of the Clausius-Clapeyron equation lead to the error in
Related questions
Question
Transcribed Image Text:The enthalpy of vaporization of a liquid is 14.4 kJ at 180K, its boiling point at 1 bar. The molar volumes of the
liquid and the vapor at the boiling point are 115 cm³ mol-¹ and 14.5 liter mol-¹, respectively.
a.
Use the Clapeyron equation to estimate d/d at the boiling point.
b. Now use the Clausius-Clapeyron equation to calculate dP/T at the boiling point.
C.
What is the percent error in
P/T when using the Clausius-Clapeyron equation?
dT
d. What approximations in the derivation of the Clausius-Clapeyron equation lead to the error in this
estimate?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
