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- Draw Vout versus Vin for the given values below. Vin V₂ V₁ + V V V www 5 ΚΩ Vout Student numbers from 190207066 up to 200207084 V₁=5 V, V₂ 9 V, V₁= 15 V, V_= -15 V, V= 11 V, Output High =14 V Output Low = 11 V (including) Vin 13xSin tConsider the circuit below. The frequency of oscillation is: www OF R₂ 1,0 ΚΩ C₁ 0.015 μF R₁ 1.0 ΚΩ 11 L Q₁ 2N5458 C₂ 0.015 μF 10.6 kHz 1.94 kHz 19.4 kHz 15.9 kHz www R₁ 10 ΚΩ R3 820 02 ww R₁ 10 ΚΩ ovour D₁ IN914 C3 1.0 μεDiscussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m+ j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 52 0° 26.5258 Z-90° 26.993 Z-79.325° N
- Discussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°Find T 0.5 ms 40 92 www www 892 160 92 20 mH wwwDiscussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 μF R Total 10+j0 Volts 10 Z0° 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°
- Plot the dc bias line for this circuit. www11 R₁ 1.5 ΜΩ R₂ 1.5 ΜΩ VGS (V) +30 V RD 1.1 ΚΩ 2N5459 www11 Rs 10 ΚΩ Minimum and maximum curves are from the datasheets. ID (mA) 16 -12 -10 Qmax 14 1 L L 1 -8 -6 -4 -2 12 10 8 6 4 Qmin Hó VG Rs 1 2 = 1.5 mA 4 1 6 8 10 12 14 16 18 VGQ/ What is the value of Rtoti ? 12, 472 Ry {150n R2 472 300 R6 300L R3 150 n+5V VDO EN Xtal 8ה 7 +5V Freq1 HGND | GND х Mhz Sensor0 crystal Freq26 5 Vss Out 04 PRE Xtal 1k Output HA7210IP 4 CLK CLR SN74HC7491 GND 0.01 μ GND +5V 4 +5V +5V +5V OE O/P3 0. 1µF | 47µF GND SG351P |2 x MHz GND GND Consider the Quartz Crystal Microbalance Sensor shown above, with crystal resonant frequency, x = 3.3 Mhz. You are given the following values: Active crystal area = 1.6 cm², and the change in frequency = - 10 Hz Calculate the change in mass, Am in nano gram, up to 2 decimal places. Answer:
- Firing angle=50 Degree 1:2 oVo -200/200V 5 Ohm The PIV of the Thyristor greater or equal to : 50 Hz O 133.3V. O 346.4V O 287.6V O 200V O 800V O 400V O 100V Ne here to search F7 F8 F10 F11 #3 $4 3 4 5 6. V E 41 T Y 1O G y H i - K L C V BYNIM1 eBook How much is ZT for a 100 Q R in series with a 100 2 inductor? Multiple Choice O O 100 92 1000 92 1410 92 141 2Draw a small signal AC equivalent circuit. Assume V=0 +20V Rc1 2k2 Cc 10µF R1 100k2 R Rc2 3k2 2k2 Vo 4µF Zo B = 100 Rs 1k2 R2 20k2 RE 5k2 CE 70µF Vs