Draw Lewis electron dot diagram of compound CO2 to determine the molecular polarity by drawing the polarity vectors

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter10: Fuels, Organic Chemicals, And Polymers
Section: Chapter Questions
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Draw Lewis electron dot diagram of compound CO2 to determine the molecular polarity by drawing the polarity vectors
Base your answer to the question on the information below and on your knowledge of chemistry.
Wood is mainly cellulose, a polymer produced by plants. One use of wood is as a fuel in campfires, fireplaces, and
wood furnaces. The molecules of cellulose are long chains of repeating units. Each unit of the chain can be
represented as C&H10Os. The balanced equation below represents a reaction that occurs when C&H10Os is burned in
air.
C6H10OS(s) + 6O2(g) → 6CO2(g) + 5H2O(g) + heat
8. Show a numerical setup for calculating the percent composition by mass of carbon in C,H10OS (gram-formula
mass = 162.14 g/mol).
lor12-2g
729
: 44.41%
x 10 0
162.14
9. Calculate the mass of CO2 (gram-formula mass = 44.01 g/mol) produced when 0.64 kg of cellulose is completely
combusted to the nearest hundredth.
0.64 ng
10009
%3D
3.95 ho
162.14g mo)
3.95 mol CÇH00 05x b mol
- 23.7mol
I mal c ctb oS
(44.01mol) (23. 7 mol) 1043-0ug
0. Draw Lewis-electron dot diagram of compound CO2 and determine the molecular polarity by drawing the
polarity vectors.
Transcribed Image Text:Base your answer to the question on the information below and on your knowledge of chemistry. Wood is mainly cellulose, a polymer produced by plants. One use of wood is as a fuel in campfires, fireplaces, and wood furnaces. The molecules of cellulose are long chains of repeating units. Each unit of the chain can be represented as C&H10Os. The balanced equation below represents a reaction that occurs when C&H10Os is burned in air. C6H10OS(s) + 6O2(g) → 6CO2(g) + 5H2O(g) + heat 8. Show a numerical setup for calculating the percent composition by mass of carbon in C,H10OS (gram-formula mass = 162.14 g/mol). lor12-2g 729 : 44.41% x 10 0 162.14 9. Calculate the mass of CO2 (gram-formula mass = 44.01 g/mol) produced when 0.64 kg of cellulose is completely combusted to the nearest hundredth. 0.64 ng 10009 %3D 3.95 ho 162.14g mo) 3.95 mol CÇH00 05x b mol - 23.7mol I mal c ctb oS (44.01mol) (23. 7 mol) 1043-0ug 0. Draw Lewis-electron dot diagram of compound CO2 and determine the molecular polarity by drawing the polarity vectors.
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