draw a flowchart based on javascript terminology, for the following problem: recieve two whole numbers as input and output their gcd(greatest common divisor) I have attached an image for reference how the flowchart should look like
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draw a flowchart based on javascript terminology, for the following problem:
recieve two whole numbers as input and output their gcd(greatest common divisor)
I have attached an image for reference how the flowchart should look like.
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Solved in 3 steps with 1 images
- del(int n){ j=(n/3)-1 while (n>0) for(i=n to i=j*3){ print "i"; 5. n--; }//end for 7 j=j/3; }//endwhile }//del() what is the asymptotic run time of del? anyalse each line and what is teh final run time is teh answer O(n^2/3)?There are five errors in this code. Correct the errors and make the code work. Explain what are the errors found. import java.util.Scanner; //Testing.java //Displays running total of numbers in lines of standard //input correct to two decimal places. //Uses an out of range number (100) to quit. public class TWODPS{ public static void main (String [] args) { Scanner input new Scanner (System.in); double total=0; boolean flag=true; System.out.println ("Use an out of range entry 100 to quit."); while (flag) { System.out.println ("Enter a number on a line:"); double d = input.nextDouble (); if (outofRange (d) ) { flag=false; else{ dispTwoDPs ("The number value is: ",d); total = total + d; dispTwoDPs ("The total is: ",total); System.out.println (); System.out.println ("Next."); } //end of else }//end of while System.out.println ("You quit."); }//end of main static boolean outOfRange (double d) { if (d>-100) return true; if (d>100) return true; return false; }Write in Java: Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binary. For an integer x, the algorithm is: As long as x is greater than 0 Output x % 2 (remainder is either 0 or 1) x = x / 2 Note: The above algorithm outputs the 0's and 1's in reverse order. You will need to write a second function to reverse the string. Ex: If the input is: 6 the output is: 110 Your program must define and call the following two methods. The method integerToReverseBinary() should return a string of 1's and 0's representing the integer in binary (in reverse). The method reverseString() should return a string representing the input string in reverse. public static String integerToReverseBinary(int integerValue)public static String reverseString(String inputString) LabProgram.java: import java.util.Scanner; public class LabProgram {/* Define your method here */ public static void main(String[] args) {/* Type your code…
- code in java pls Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.Given L = {w = {a, b}*: |w| is even}, the correct statements are: (aa U ab Uba U bb)* is a regular expression that generates L. (ab Uba)* is a regular expression that generates L. aa U ab U ba U bb is a regular expression that generates L. ab U ba is a regular expression that generates L.Need help in python. Problem: 2D random walk. A two dimensional random walk simulates the behavior of a particle moving in a grid of points. At each step, the random walker moves north, south, east, or west with probability 1/4, independently of previous moves. Compose a program that takes a command-line argument n and estimates how long it will take a random walker to hit the boundary of a 2n+1-by-2n+1 square centered at the starting point. //Given codeImport stdioImport randomImport sysn = int(sys.argv[1])//write code herestdio.write('The walker took ')stdio.write(c)stdio.writeln(' steps')
- The following function f uses recursion:def f(n):if n <= 1return nelsereturn f(n-1) + f(n-2)5Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n):a <- 0b <- 1if n = 0return aelsif n = 1return belsefor i in 1..nc <- a + ba <- bb <- creturn b b) def f(n):a <- 0i <- nwhile i > 0a <- a + i + (i-1)return a c) def f(n):arr[0] <- 0arr[1] <- 1if n <= 1return arr[n]elsefor i in 2..narr[i] <- arr[i-1] + arr[i-2]return arr[n] d) def f(n):arr[0..n] <- [0, ..., n]if n <= 1return arr[n]elsea <- 0for i in 0..na <- a + arr[i]return adel(int n){ j=(n/3)-1 while (n>0) for(i=n to i=j*3){ print "i"; 5. n--; }//end for 7 j=j/3; }//endwhile }//del() what is the asymptotic run time of del? anyalse each line and what is the final run timeIn python, Problem Description:Sheldon and Leonard are physicists who are fixated on the BIG BANG theory. In order to exchange secret insights they have devised a code that encodes UPPERCASE words by shifting their letters forward. Shifting a letter by S positions means to go forward S letters in the alphabet. For example, shifting B by S = 3 positions gives E. However, sometimes this makes us go past Z, the last letter of the alphabet. Whenever this happens we wrap around, treating A as the letter that follows Z. For example, shifting Z by S = 2 positions gives B. Sheldon and Leonard’s code depends on a parameter K and also varies depending on the position of each letter in the word. For the letter at position P, they use the shift value of S = 3P + K. For example, here is how ZOOM is encoded when K = 3. The first letter Z has a shift valueof S = 3 × 1 + 3 = 6; it wraps around and becomes the letter F. The second letter, O, hasS = 3 × 2 + 3 = 9 and becomes X. The last two letters…
- Exercise 2: In probability theory, one problem that often arises is determining the number of ways in which p objects can be selected from n distinct objects without regard to the order in which they are selected. Such selections are called combinations. The number of combinations of p objects from a set with n objects is C (n, p) and is given by: п! С(п, р) — (п- р)! * p! Write a Python program which will calculate and display on the screen the number of possible combination C based on the values of n and p; where both n and p are positive integers less than 21 and n >p. Implement and use at least the following three functions: fact(.): A function when passed a positive integer value, will calculate and return the factorial of that number. comb(..): A function when passed n and p (n: total number of objects and p: number of objects taken at a time) will calculate and return the total number of possible combinations (using the formula above). It calls function fact.) main(..): reads…mplement a Java program that applies the Newton-Raphson's method xn+1 = xn – f(xn) / f '(xn) to search the roots for this polynomial function ax6 – bx5 + cx4 – dx3+ ex2 – fx + g = 0. Fill out a, b, c, d, e, f, and g using the first 7 digits of your ID, respectively. For example, if ID is 4759284, the polynomial function would be 4x6 – 7x5 + 5x4 – 9x3+ 2x2 – 8x + 4 = 0. The program terminates when the difference between the new solution and the previous one is smaller than 0.00001 within 2000 iterations. Otherwise, it shows Not Found as the final solution.Maclaurin series are a type of Mathematic series expansion in which all terms are nonnegative real powers of the variable. The Maclaurin series expansion for sin(x) is given by the following formula that is valid for all real values of x such that x is in radians (Note that: radians(x) = x X 1/180): sin(x) = x - 3! 5! Implement a Java program to compute the value of Maclaurin series expansion for sin(x) where x is a nonnegative real value according to the following: a. Write a java method named Factorial that takes as an argument an integer value n and returns the mathematical factorial n! of n as a long value such that: n! = n x (n – 1) x (n – 2) ... × 2 x 1 b. In the main method: i. Ask the user to enter the value of the angle x to be calculate in the Maclaurin series expansion for sin(x) as given above. x Should be entered in degrees, i.e., 0° < x< 360° and then converted into radians using the formula: (radians(x) = x × 1/180). ii. Ask the user to enter the number of terms to be…