Determine the solution of the initial value problem 1. у" + 4y' + 5у%3D 35е4*, У (0) %3D — 3, у'(0) %3D 1
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- Solve for u. 2u^(2)+7u+32=(u-2)^(2) If there is more than one solution, separate the uFind a real general solution. Show the details of your work: 1. 5х2у" + 23ху' + 16.2у %3D 0 2. х?у" + 0.7ху' — 0.1у %3D 0 3. х^у" — 0.7ху' - 0.1у %3D 0Solve: yv + 10yiv + 53y''' + 124y'' + 100y' = 0 a. y = C1e3xcos4x + C2e3xsin4x + C3e-2x + C4xe-2x + C5 b. y = C1e-3xcos4x + C2e-3xsin4x + C3e-2x + C4xe-2x + C5 c. y = C1e-3xcos4x + C2e-3xsin4x + C3e2x + C4xe2x + C5 d. y = C1e3xcos4x + C2e3xsin4x + C3e2x + C4xe2x + C5