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*Phenotypes means the traits that an individual contains can be easily observable
* Ex: colour, Height , eye colour, hair ,shape etc
*Genotype means genetic arrangement which makes up the trait that an organism was inherited from their parents
*Ex:a gene encodes hair colour
*Blue allele(B) is dominant to black allele(b)
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- 4. STATEMENT: A woman who has blood type B positive has a daughter who is type 0 positive and a son who is type A negative. a) What is the genotype for the woman, daughter, son and man? Woman Daughter Son Man Genotype b) The woman and the man surprising are having a third child. What are the possible genotypes and phenotypes for their third child?2. Given: GGWw X ggww Yellow, Round Green Wrinkled Problem: Determine the F2 Genotype and Phenotype2. STATEMENT: A woman and man both do not have sickle-cell anemia, but both had one parent who had sickle cell. Sickle-cell is an autosomal (somatic) recessive trait. a) What is the genotype for the woman, man and each of their parents? b) This couple unexpectedly is going to have their first child. i. What's the probability that their child will have not have sickle cell like the couple? ii. What's the probability that the child will have sickle cell like one the grandparents?
- 1. Given the karyotype shown here, is this a male or a female? What would the genotype/phenotype of this individual be?1. Given: CcWwGg X CcWwGg Full, Round, Yellow Full, Round, Yellow Recessive Traits: Constricted, Wrinkled, Green Problem: Determine the F1 PhenotypeA. For the following genotypes state the ABO blood phenotype. JAJA |B|O_ 101⁰_ |A|B_ B. Using genetic diagrams, show how it is possible for a couple with a type A mother and a type B father can have a child with type O blood. C. Using genetic diagrams show how a type AB person with a type O partner have offspring that share neither of their phenotypes.
- 4. Consider the characteristics and pedigree of a couple: Woman: has normal vision but mother is color blind has normal blood clotting but father is hemophiliac not bald but both parents are bald Man: father is colorblind but mother has normal vision both parents have normal blood but the brother is hemophiliac bald but both parents are not bald. a) Give the genotypes of the following: i. ii. man i. woman's mother and father iv. man's mother and father woman1. Study the given alleles. Write the correct phenotype for each genotype. X – normal Gen otype xC - Color-blind Phenotype XX XY XXC xCY 2. Study the given alleles. Write the correct genotype for each phenotype. xH - Hemophiliac Phenotype X- normal Gen otype Hemophiliac female Hemophiliac male Normal female carrier of the gene Normal male Normal female 28 3. Determine the genotype and phenotype of the offspring. A color-blind mother (XCx) married a normal sighted (XY) father. Genotype: Phenotype: Genotype: Phenotype: Genotype: Genotype: Phenotype: Phenotype: a. There are b. There are c. There are d. There are % normal sons. % normal daughters. % color-blind sons. % color-blind daughters. % normal female, carrier of the disorder. or or or or e. There are orD. Sex-linked In humans, hemophilia is a sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won't ever be carriers). 1. Show the cross of a man who has hemophilia with a normal woman. What is the probability that their children will have the disease? H H = female, normal H h X X = female, carrier h xxn XHY X" Y 2. A woman who is a carrier marries a hemophiliac man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be? 3. A woman who has hemophilia marries a normal man. How many of their children will have hemophilia, and what is their sex? = female, hemophiliac = male, normal = male, hemophiliac
- IX. The blood of several members of a particular family was determined, and the results are tabulated below. Individual Blood Type Genotype Father Mother B Child 1 AB Child 2 B. Child 3 Grandfather (mother's side) Grandmother (father's side) AB Assuming that no adultery or adoption took place for all generations, answer the following questions: a. Give the most probable genotype for each individual. Supply your answers on the table above. b. What is/are the most probable genotype(s) for the grandmother on the mother's side? c. If the father and the mother decide to have two more children, what is the probability that the first would be female type A and the second male type AB?The following scenario can be seen on Ch 29 Clinical case study on Heredity (27-year-old with normal pregnancy): Mrs. Rodriguez’ blood type is type O, and her husband’s is type A. She is currently pregnant and she would like to know what type of blood her baby will have. For discussion 7 please answer the following questions: What are the genotype and phenotype of Mrs. Rodriguez? What are the genotype and phenotype of Mr. Rodriguez, given that Mr. Rodriguez’s mother has O blood type and his father has A blood type? (use Punnett Square on your worksheet to find out the genotype of Mr. Rodriquez) What is the probability that Mrs. Rodriguez’s baby will have O blood type? A? B? AB? (use Punnett Square as your worksheet) Type O =______% Type A = _____ % Type B =______% Type AB =______%b. The following diagram shows a family tree of individuals with haemophilia. B i. Based on an X-linked recessive pattern of inheritance, work out the likely genotypes of the individuals indicated by the letters. Individual A Individual B Individual C GENOTYPE ii. If individual C has children with a normal male, what are the chances that they will have haemophilia? Explain your answer fully. iii. If individual C has children with a normal male, what are the chances that their daughters will be carriers of the condition? Explain your answer fully.