Determine the currents I₁, I2, and I3 for the electrical network shown in the figure. (Assume V₁ = 3 V and V₂ = 4 V.) I₁ = ХА XA 12 = I3 = 1 A www R₁ = 492 12 ww R₂ = 392 R3 = 192 V₁ V₂
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- with Kirchhoff's laws with the electric current shown in figure below, the following equations are found. Find the indicated currents (in A) I1, I2 and I3. a)I1=3.15A, I2=1.87A , I3=0.19A b)I1=0.15A, I2=2.87A , I3=3.19A c)I1=2.15A, I2=3.87A , I3=1.19A d)I1=1.15A, I2=4.87A , I3=3.19APlease explain why this is the equation to solve for I1, I2, and I3 using nodal analysis. I need to know why did it became positive or negative. Thank you.Find I1,I2 and I3 in the given figure using Kirchhoff's Laws
- Task 3 A three phase, four wire star connected load consisting of: ZR: a resistor of 9500 in series with a 3H inductor ZB: a resistor of 1950 ZY: a resistor of 1950 in series with a 4µF capacitor Using the equipment available in the power lab (Room T017), connect the given load to a three-phase supply available in the lab and: 3.1. Determine the current of each line and the neutral current and measure the total power supplied by the source. 3.2. Analytically, calculate all currents and the total power and compare with those obtained in measurements. 3.3. Device a method and measure the waveform of the neutral current. Discuss the obtained waveform and the reason for any distortion in the waveform 3.4. Validate your calculations using computer simulationDetermine the currents I1, I2, I3,I4, I5, and I6 for the electrical network shown in the figure.E Figure 1. R₁ L₁ M 1.Calculate coefficient of coupling k. R₂ L₂ 1₂ R₁ E = 230V 20°, R₁ = 100, R₂ = 0.50, R₂ = 2002, L₁= 10 H, L₂ = 26 mH, M = 0.5 H, f= 50Hz
- a) Find the currents I1, I2, and I3 flowing on the circuit in the figure. b) What current flows in the opposite direction to the assumed direction? c) Using kirchoff's rules, calculate the potential differences between points c and e by following the following ways. path 1 = c-d-e path 2 = c-d-a-e path 3 = c-b-a-eGiven n2 = 510, what is n₁? 5415° V 3060 85 1530 O 170 +21 000 ell n₁: N₂ + 30415° VA line consist of a pure resistance and a coil in series. The power dissipated in the resistance is 500 Watts and the drop across it is 100V. The power dissipated in the coil is 100 Watts and the drop across it is 50 V. What is the voltage at the sending end?
- 2. Solve the equations for the loop currents I1, I2 and 13 if the mesh-current analysis produces the following three equations: 2020° = (5 + 3 – j4)I1 – (3 – j4)I2 %3| 10Z90° = (3 - j4 + 2)I2 – (3 – j4)I1 – 213 -15Z0° – 10 ° = (12 + 2)I3 – 212R1 = 50 ohm R3 R2 RI R2 = 25 ohm I2 El = 5 volt R3 = 75 ohm E2 E2 = 4 volt [Q3] Analyze the following electrical circuit by finding the currents (I1, 12 and I3) using Gauss-elimination method60. An RLC series circuit connected to a 110-volt and 50-cycle AC source, contains the following series resistances and reactances: R1=10 ohm, R2= 15, XL1=20 ohms, XL2=25 ohms, XC= 40 ohms. Find the real power. a. 65.3899 b. 392.4372 c. 397.848 d. 588.6559