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- 2. One of the common methods used to determine phosphorus in urine isto treat urine with molybdenum(VI) resulting in a complex compoundof 12- molybdophosphate and then reduced using ascorbic acid produces a blue-colored compound called molybdenum blue (max = 650 nm). A patient's urine sample collected over 24 hours produced 1122 mL of urine. A total of 1 mL of the sample was treated with Mo(VI) and ascorbic acid and diluted until it reached a volume of 50 mL. A calibration curve is also prepared by treating 1 mL of standard phosphate solution in the same way. The absorbance of the standard solution and the sample was then measured at a wavelength of 650 nm and produced the following data: Solution Absorbance at λ 650 nm Phosphate 1 ppm Phosphate 2 ppm Phosphate 3 ppm Phosphate 4 ppm Urine sample 0,230 0.436 0,638 0,848 0.518 a. Create a calibration curve for the data and determine the slope, intercept, and R values of 2! Determine the concentration of phosphates found in urine samples…b. EDTA cannot be used as a primary standard always. When can EDTA be used as a primarystandard ? Give reason why EDTA is used in complexometric titrations.c. Use the Table to answer the questions below Concentration (M) Absorbances 0.20 0.36 0.40 0.50 0.60 0.65 0.80 0.75 Plot the graph and attach your plot. Use the table to answer the following question i. If 1.1 cm cell was used. Calculate the molar absorptivity of Cr(Il). ii. What is the concentration of a compound with absorbance 0.60, if 2 cm cell is used.
- AZ91 alloy; a) What is its chemical composition? b) Which of the strength increasing methods are suitable and which are not? Explain c) Is nitration suitable as one of the surface hardening methods? Please explain1. Why is it necessary to use a buret for measuring standard AgNO3 solution in volhard method? 2. What is the effect of discolored AgNO3 on the concentration of KSCN? 3. Why is necessary to use boiled 6N HNO3 in volhard? 4. why is the titration done with vigorous swirling? 5. A solution of AgNO3 is added to a solution containing 0.100 Cl- and 0.100M CrO4-, at what Ag+ concentration will Ag2CrO4 begin to precipitate? and what will be the concentration of the less soluble compound when the more soluble one begins to precipitate?Explain why Anodic Stripping Voltammetry (ASV) is considered superior over analytical techniques in terms of detection limit.
- water sample is determined through a spectrophotometric method based on the reaction of phosphate ion with molybdate ion, by originating a yellow complex. Calibration standards (P1 to P5) are prepared as follows: different volumes of a 102.2 mgL1 phosphate solution are added to several 100 mL volumetric 1. The content of phosphate in a flasks. Then, 10 mL of diluted HCI, 10 mL of 1% molybdate ion solution, and 10 mL of 0.75% oxalic acid solution are added to every flask, and finally water is added up to the volumetric mark. Samples are prepared in the same way, adding different sample volumes instead of phosphate standard solution. Absorbance of all solutions is measured at 360 nm, and the following data are obtained: Added volume Absorbance at 360 nm P1 2a 0.109 P2 5a 0.249 P3 10a 0.501 P4 15a 0.748 Р5 20a 1.008 Blank 0.000 Sample 20b 0.624 (a) mL of 102.2 mg L' phosphate standard solution. (b) mL of sample Calculate the concentration of phosphate in the water sample expressed in mg…a. What mass of Ag2SO4 is formed when 34 mL of 0.300 M AgNO3 are mixed with 26 mL of 30.0 g/L Na2SO4? b. Potassium can be determined by flame emission spectrometry (flame photometry) using lithium internal standard. The following data were obtained for standard solutions of KCI and an unknown containing a constant, known amount of Lil as the internal standard. The intensity of a blank was 0.04. Calculate the concentration of K in the unknown. ck, ppm Intensity of K emission Intensity of Li emission 5.0 34.7 5.8 20.0 110.2 9.1 Unknown 57.3 6.8Where does the strongest IMF occur in liquid ethanol?
- One common way to determine Phosphorous in urine is to treat the sample after removing the protein, with molybdenum (VI) and then reduce the 12-molybdophosphate with ascorbic acid to give an intense blue color species called molybdenum blue. The Absorbance of molybdenum blue can be measured at 650 nm. A patient produced 1122 mL of urine in 24 hours. A 1.00 mL aliquot of the sample was treated with Mo(VI) and ascorbic acid and diluted to a volume of 50.00 mL. A calibration plot was prepared by treating 1.00 mL aliquots of Phosphate standard solutions in the same manner as the urine sample. The absorbances of the standards and the urine sample were obtained at 650 nm, and the following results were obtained: Solution absorbace at 650 nm 1.00 ppm P 2.00 ppm P 3.00 ppm P 4.00 ppm P Urine sample 0.230 0.430 0.630 0.840 0.518 (1) Construct a plot of the calibration curve and find the slope, intercept and the number of ppm of P in the sample. (ii) What mass in grams of phosphorous was…The following are the advantages of the dropping mercury electrode except... It has a wide negative voltage scan range. It does not need to electroalyze all the analyte in the sample solution. It can refresh the surface of the working electrode. It uses mercury for the analysis.Mention the optimum conditions required for good performance of: i. Chelating agent in metal separation ii. Rule of primary ions in separation by ion exchanger Tii. Distribution ratio in liquid-liquid and liquid solid separations. v. Ion exchange (Type and mechanism)