dentify the genotypes of the parents and offspring given that there are baby rabbits with the following coat color: 1 himalayan, 1 albino, and 2 chinchilla.
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Identify the genotypes of the parents and offspring given that there are baby rabbits with the following coat color: 1 himalayan, 1 albino, and 2 chinchilla.
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- A woman homozygous dominant for albinism marries a man who is homozygous recessive for albinism. What are the possible genotypes and phenotypes percentages for their offspring?From the BbHh x BbHh dihybrid cross where BB or Bb represented full melanin and bb represented no melanin, and where HH or Hh represented black fur and hh represented brown fur, interpret the 9 : 3 : 3 : 1 phenotypic result from the F generation. Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a 9 had no melanin and black fur, 3 had no melanin and brown fur, 3 had no melanin and black fur, 1 had no melanin and brown fur b 9 had no melanin and brown fur, 3 had full melanin and brown fur, 3 had no melanin and black fur, 1 had full melanin and black fur c 9 had no melanin and black fur, 3 had full melanin and brown fur, 3 had no melanin and black fur, 1 had no melanin and brown fur d 9 had full melanin and black fur, 3 had full melanin and brown fur, 3 had no melanin and black fur, 1 had no melanin and brown furComplete the punnet square and indicate the genotype and phenotype of the following monohybrid cross: Black fur is dominant (B) to brown fur (b) in dogs, if the female is heterozygous and the male is recessive, fill out the following Punnett square and provide all the phenotypes and genotypes of their possible puppies.
- Identify the phenotype for each number represented in the 3:1 ratio.The blood serum from one individual (let’s call this person individual 1) is known to agglutinate the red blood cells from a secondindividual (individual 2). List the pairwise combinations of possible genotypes that individuals 1 and 2 could have. If individual 1is the parent of individual 2, what are his or her possiblegenotypes?In addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.
- A phenotypic ratio of 6:6:4 is possible between a male who is heterozygous free earlobes and heterozygous freckles, and a female who is homozygous free earlobes and heterozygous. The genotype of the female is written this way Eeff. Key: E = free earlobes e = attached earlobes F = freckles f = no freckles O If both statements are FALSE If both statements are TRUE O If the first statement is FALSE and the second statement is TRUE O If the first statement is TRUE and the second statement is FALSEIn guinea pigs, the black coat (B) is dominant over the white coat (b), and straight hair (H) is dominant over curly hair (h). Using a Punnett square, complete the cross between a heterozygous black, curly-haired individual and a homozygous straight-haired, white individual. State the parent genotypes and gametes, and the F1 phenotypes and genotypes.In the Bombay phenotype, a homozygous recessive individual hh appears to have blood type O because she is unable to produce the H substance, which is required to make the A or B blood-type antigens. HH or Hh individuals normally produce H substance. What is the probability that a child will test as type AB blood from parents with the following genotypes? IAIO Hh X IBIA hh 3/16 1/8 1/4 3/4 1/2
- A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. One parent with the Achondroplasia phenotype and a normal parent have 2 children. Both children have the Achondroplasia phenotype NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.In the Bombay phenotype, a homozygous recessive individual hh appears to have blood type O because she is unable to produce the H substance, which is required to make the A or B blood-type antigens. HH or Hh individuals normally produce H substance. What is the probability that a child will test as type AB blood from parents with the following genotypes? IAIO Hh X IBIO Hh 1/4 3/4 3/16 1/2 7/16