Decide what H and C atoms in your final product should fit the reported chemical shifts and answer any additional questions. The literature data are for the free base fluoxetine product not the oxalate product. 1HNMR (60 MHz, CDCI3) d 1.9-2.2 (10H, m), 5.2 (1H, t), 6.8-7.4 (9H, m). 1°C NMR (91 MHz, CDCI3) d 160.5, 141.0, 128.6, 127.6, 126.5, 125.7, 122.8, 124.3 (q. J = 267 Hz), 122.5 (q. J = 30 Hz), 115.7, 78.5, 55.7, 45.5, 36.8. %3D 1. For the 13C spectrum: notice the signals at 124.3 and 122.5 are split into quartets. This is unusual for the 13C NMR of many organic compounds. Why is this observed in the spectrum for fluoxetine.

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Decide what H and C atoms in your final product should fit the reported chemical shifts and
answer any additional questions. The literature data are for the free base fluoxetine product
not the oxalate product.
HNMR (60 MHz, CDCI3) d 1.9-2.2 (10H, m), 5.2 (1H, t), 6.8-7.4 (9H, m).
13C NMR (91 MHz, CDCI3 ) d 160.5, 141.0, 128.6, 127.6, 126.5, 125.7, 122.8, 124.3 (q. J =
267 Hz), 122.5 (q, J = 30 Hz), 115.7, 78.5, 55.7, 45.5, 36.8.
%3D
1. For the 13C spectrum: notice the signals at 124.3 and 122.5 are split into quartets. This is
unusual for the 1°C NMR of many organic compounds. Why is this observed in the spectrum
for fluoxetine.
Transcribed Image Text:Decide what H and C atoms in your final product should fit the reported chemical shifts and answer any additional questions. The literature data are for the free base fluoxetine product not the oxalate product. HNMR (60 MHz, CDCI3) d 1.9-2.2 (10H, m), 5.2 (1H, t), 6.8-7.4 (9H, m). 13C NMR (91 MHz, CDCI3 ) d 160.5, 141.0, 128.6, 127.6, 126.5, 125.7, 122.8, 124.3 (q. J = 267 Hz), 122.5 (q, J = 30 Hz), 115.7, 78.5, 55.7, 45.5, 36.8. %3D 1. For the 13C spectrum: notice the signals at 124.3 and 122.5 are split into quartets. This is unusual for the 1°C NMR of many organic compounds. Why is this observed in the spectrum for fluoxetine.
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