Decane (K₁ = 6.10 K mol kg ¹) and ethanol (Kb = 1.23 K mol kg ¹) have very similar enthalpies of vaporization, yet very different ebullioscopic constants (as given). Explain in one sentence.

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter9: Liquids, Solids, And Materials
Section9.2: Vaporization And Condensation
Problem 9.2PSP: What mass (g) of ethanol, CH3CH2OH(), can be vaporized at its boiling point of 78.4 C by transfer of...
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Decane (Kb = 6.10 K mol kg 1¹) and ethanol (Kb = 1.23 K mol kg ¹) have very similar enthalpies of vaporization,
yet very different ebullioscopic constants (as given). Explain in one sentence.
Transcribed Image Text:Decane (Kb = 6.10 K mol kg 1¹) and ethanol (Kb = 1.23 K mol kg ¹) have very similar enthalpies of vaporization, yet very different ebullioscopic constants (as given). Explain in one sentence.
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