D = 110 k L = 280 k %3D 30' W12 X 87 A992 steel Rectangular Snip
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A: Solution: Given: DL = 5.3 KPa LL = 2.4 KPa fc = 21 MPa fy = 345 MPa beam = 350 x 500 mm use 12 mm…
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Q: D = 110 kips L = 280 kips W12 x 87 A992 steel 30
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A: Solution Given That f'c=21 MPafy= 420 MPa
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Q: 2. Determine whether the compression member shown in the figure below is adequate to support the…
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Q: A W21 × 101 is used as a compression member with one end fixed and the other end free. The length is…
A: Given data, W21x101 Length = 9 m Fy = 345 MPa
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Q: Q2: The compression member shown in Figure below is pinned at both ends and supported in the weak…
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Q: Q3/ Calculate the ultimate capacity for the beam of cross section shown in Fig.(2). Use f'c- 30 MPa…
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Q: Assume fy=345MPa and f'c=21 MPa. a. From the provided steel reinforcement, will the steel yield? b.…
A: Triangular beam Width 375mm Depth 375mm fc=21mpa fy=345mpa
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Q: Q1: Find the Maximum Uniform Live Load can be applied on the beam shown below, f= 400 Mpa, f=25 Mpa.…
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Q: Question 3. A W310x118 is to be used as a column having a total length of 12 meters. Assume G40.21…
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A: step 1-
Determine whether the compression member shown in Figure is adequate to support the given service loads.
a. Use LRFD.
b. Use ASD.
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- The rigid plate ABC shown in figure 2, was positioned on top of two identical steel posts, and the aluminum post was 0.1mm shorter than the steel posts at temperature of 50°C, if the allowable compressive stress in steel is limited to 120 MPa and in aluminum to 150 MPa, what is the maximum possible load P that can be supported on the rigid plate at temperature of 10°C ?Can somebody show me how to identify the following members (highlight them if needed, I truly need to know) ? AD AE AF BD CF DE EF 60 140 mm(1) 21" 3" 4#9 bood 14" (1) Ec = ? (2) fr=? (3) Mer=? (5) #4 (4) When M = 70 & Mn = ? fé = 5 ksi Grade 60 Steel NWC. ft-k I 1R-2 Dr b=14", h=24" #4 tied stirrups. 4 #9 Rebars. fe=? Please write down units properly in the final answers. fs=?
- 0-075 2.80 m 3.65 m DOOR: 0.80m X 2.10m WINDOW: 0.40m X 1.80m 0075 0-075 5.85m 0.075 2.50 m REQUIREMENT: PCS- 14" THICK INTERIOR PLYWOOD WALLS PCS- 14" THICK EXTERIOR HARDIFLEX WALLS PCS- 1"X4"X12' T&G FLOORINGsted ingid 250MM B k steel bar bolt AUR rigid bar 12 mm thick 8 mm Brass 350mm Jointd 16 mene thick 350mm JointB 250 mm Xg = 20x10% Eg = 90 G Pa -6 A, = 12x10/0 Es = 200 G Pa thickness> 16 mm 8 mm bolt %3D 12 mmi thick shear strength f bolf bearing streng th of holt= 100 la 50 MPa %3D Assume no failure will take place in steel or brass. Temperature chauge brass steel on Temperature change on Determine thai can be applied to system - the maxDetermine the nominal axial compressive strength of the members shown in the following figure.
- Permissible As in sechion to ensure tensile Compute the design strength of beam shown it 420 MPa , fc = 30 MPa . check the maximum %3D Permissible As in sechion to ensure tensile failure. 4¢25 stimpp10 q00 8432 300 mmO 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading conditionDetermine the moment of inertia of the composite area shown beow about the centroidal y- axis and its Ky 5in 1 in 2in -3in 3in Text X
- Figure 3 - Word A kennedy_asamoah@yahoo.com me Insert Design Layout References Mailings Review View Help O Tell me what you want to do Calibri (Body) Aa - E -E-- E E py AaBbCcD AaBbCcDe AaBbC AaBbCcE AaB AaBbccc 4aBbCcDt P Find- mat Painter BIU - abx X. x' A - aly - A - 1 Normal I No Spac. Heading 1 Heading 2 ab Replace Title Subtitle Subtle Em. ard A Select Font Paragraph 1 2 3 4 5 . 6 1 Styles Editing 10 11 12 13 14. 15 A Sluice gate is a device that is fitted in a sluice or fluid canal to operate and control the fluid flow. Oil flows in a canal and the sluice gate has a breadth of 8 m wide and6 m deep. Let the oil density = 850 kg/m3. Determine: the center of pressure (COP) acting on the sluice gate, the top of the gate is 3 m below the oil surface. of 2 307 words English (South Africal 17:01 A ) a ENG 2021/02/03 O Type here to search DELL 近Calculate the allowable (ASD) block shear rupture strength (kN) of a C230x22, attached through the web with six M20 bolts as shown. The yield strength of the steel is 345 MPa and the ultimate tensile strength is 483 MPa. C230x22 64.5 Ο Ο Ο OO 64.5 50 75 75 +steel Design صنب