Current Attempt in Progress A car starts from rest with an acceleration of 6.3 m/s2 which decreases linearly with time to zero in 9.6 seconds, after which the car continues at a constant speed. Determine the time t required for the car to travel 470 m from the start. Answer: t = S Save for Later Using multiple attempts will impact your score. 10% score reduction after attempt 1 Attempts: 0 of 3 used Submit Answer

Current Attempt in Progress A car starts from rest with an acceleration of 6.3 m/s2 which decreases linearly with time to zero in 9.6 seconds, after which the car continues at a constant speed. Determine the time t required for the car to travel 470 m from the start. Answer: t = S Save for Later Using multiple attempts will impact your score. 10% score reduction after attempt 1 Attempts: 0 of 3 used Submit Answer

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A subway train stops at two stations that are 2 km apart. The max. acceleration and deceleration of the train are 2 m/s2 and 1.6 m/s?, respectively and the max. allowable speed is 20 m/s. Which of the following gives the time to travel at a constant speed of 20 m/s? a-t graph: 2 m/s? t3 t2 -1.6 m/s? Select the correct response: 100 s 88.75 s 87.85 s 80.25 s
Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A 2500-ib automoble is moving at a speed of 50 ml/h when the brakes are fully appled, causing all four wheels to skid. Determine the time required to stop the automobile on dry pavement (k= 075). The time requtred to stop the automobile is 23 Os.
An engineer has mounted both wheel speed and acceleration sensors to a racing car. The car enters a corner maintaining a constant lateral acceleration of 15m/s2. The car applies its brakes and experiences constant deceleration over a period of 1s reducing its forward velocity from 100km/h to 70km/h. Determine the following: a) Tangential acceleration of the vehicle. b) Magnitude of vehicle acceleration. c) Plot the radius of curvature vs. time for the 1s corner entry.
Current Attempt in Progress In an archery test, the acceleration of the arrow decreases linearly with distances from its initial value of 15400 ft/sec² at A upon release to zero at B after a travel of 31.1 in. Calculate the maximum velocity v of the arrow. Answer: v= i Save for later Bl 31.1" ft/sec Attempts: 0 of 3 used Submit Answer
Data has been gathered from a lifting system used to remove spent RBMK fuel rods from the spent rod pool into long term safe storage. At present the spent rods are winched up from the pool and then lowered into concrete barrels in a second pool. When it is positioned properly the winch is released and the rod is allowed to drop in. The following calculation is based on data gathered from the present set up. Time taken to lowered into concrete barrels = 10 Seconds Winch drum diameter = 0.9m Mass of load = 185 kg Initial velocity = 0 m/s Distance travelled = 6m You have been asked to use this information to determine: The final linear velocity of the load The linear acceleration of the load The final angular velocity of the drum The angular acceleration of the drum The tension force in the cable The torque applied to the drum In determining the above quantities, you should clearly state the formulae used and apply dimensional analysis techniques to show that all values/units used…
At a football tryout, a player runs a 40-yard dash in t2 = 5.00 seconds. If the reaches his maximum speed at the 14-yard mark L1 with a %3D constant acceleration and then maintains that speed for the remainder of the run, determine his acceleration over the first 14 yards, his maximum speed, and the time duration of the acceleration. t =0 Amswers: His acceleration: i ft/sec2 = His maximum speed: V = ft/sec The time duration of the acceleration: t= sec %3D
A human-powered vehicle (HPV) team wants to model the acceleration during the 260-m sprint race (the first 60 m is called a flying start) using a= A- Cv2, where a is acceleration in m/s2 and v is the velocity in m/s. From wind tunnel testing, they found that C = 0.0012 m-1 . Knowing that the cyclist is going 100 km/h at the 260-meter mark, what is the value of A?
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Many car companies are performing research on collision avoidance systems. A small prototype applies engine braking that decelerates the vehicle according to the relationship a = -k√t, where a and fare expressed in m/s² and seconds. respectively. The vehicle is traveling at 24 m/s when its radar sensors detect a stationary obstacle and it takes the prototype vehicle 4 seconds to stop. Determine the expressions for its velocity and position as a function of time. (You must provide an answer before moving on to the next part.) The expression for velocity as a function of time is v=-[ The expression for position as a function of time is x(0)=- 3/2, 5/2
TOPIC: KINEMATICS Specific Instructions: Solve each problem NEATLY and SYSTEMATICALLY. Show your COMPLETE solutions and BOX your final answers. Express all your answers in 2 decimal places. Problem: Two vehicles A and B travel in a level road in the same direction at 100 kph. B is 80 m ahead of A when brakes are applied in B causing it to decelerate at the rate of 2.2 mps? . In what time will Car A overtake B and how far will each have to travel?
Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. Block B starts from rest and then moves to the right with a variable acceleration given by the acceleration-time curve. Determine:(a) the acceleration(b) the velocity of block A at t = 3.71 s.*dont copy other experts' answer, i'm looking for a different approach in solution can you please verify which among these two solutions is coreect?Solution 1: Step 1 Let T is the tension in each rope so 3T is acting on block B and 2T is acting on block A. So , 3T×aB=2T×aA×aB=2T×aA Hence,aA =32aBHence,aA =32aB Step 2 acceleration of block B = 0.29 ft/s2 (from graph) a)acceleration of block A (t=3.71s)= 32×0.29 ft/s2 =0.435 ft/s232×0.29 ft/s2 =0.435 ft/s2 b) Velocity of block B at (t = 3.71 s) = Area under the graph = 2ft/s2×1s−1ft/s2×1s+12×(2ft/s2+0.29ft/s2)×1.71s =2.96ft2ft/s2×1s-1ft/s2×1s+12×(2ft/s2+0.29ft/s2)×1.71s =2.96ft/s Velocity of block A at (t=3.71s) = 32×vB=32×2.96ft/s=4.44 ft/s Solution 2: *check the last…
Find the distance covered by object A in 10 seconds . Its initial velocity V1 = 15 m/s and its acceleration 2 m/s2 : You can use the formulae V2 - V1 = at V22 - V,² = 2 a s S = V, t + 0.5 a t2 :Choose the correct answer :Select one a. 250 m b. 30 m c. 1800 m d. 450 m
A motorcycle starts from rest at s = 0 and travels along a straight road with the speed shown by the v –t graph. (Figure 1) Determine the motorcycle's acceleration when t = 12 s Express your answer to three significant figures and include the appropriate units. HA ? m a = 0,25 Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Figure Part D Determine the motorcycle's position when t = 12 s. Express your answer to three significant figures and include the appropriate units. v (m/s) s = 48.0 m v = 1.25 5 む=5 Submit Previous Answers v = -1+ 15 v Correct t (s) 10 15 Provide Feedback Next >