Copyright Texas Sta a. If λ 0 is an eigenvalue of M, then M is invertible. All rights reserved. Copyright Texas b. If M has no free-variables, then there are no vectors in NulSp(M).sity, 2023. All Copyright Texas State University, 2023. All rights reserved. c. NulSp(A) is a subspace of the Codomain of A. State University, 2023. All rights

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 80E
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Constants: a = 2, b = 3

the following statements are FALSE. Explain why and correct them so they
are true.

Copyright Texas Sta
a. If λ 0 is an eigenvalue of M, then M is invertible. All rights reserved.
Copyright Texas
b. If M has no free-variables, then there are no vectors in NulSp(M).sity, 2023. All
Copyright Texas State University, 2023. All rights reserved.
c. NulSp(A) is a subspace of the Codomain of A.
State University, 2023. All rights
Transcribed Image Text:Copyright Texas Sta a. If λ 0 is an eigenvalue of M, then M is invertible. All rights reserved. Copyright Texas b. If M has no free-variables, then there are no vectors in NulSp(M).sity, 2023. All Copyright Texas State University, 2023. All rights reserved. c. NulSp(A) is a subspace of the Codomain of A. State University, 2023. All rights
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