Convert the following chair conformation of the sugar a-D-galactose into a structure that shows all the cis & trans relationships as hashed (down) and wedge (up) bonds. HO 0 HO- CH₂OH ▾ HO OH . Use the wedge/hash bond tools to indicate stereochemistry where it exists. . In cases where there is more than one answer, just draw one. . Use "flat" representations of rings, not chairs, in your drawing. H₂C-O O OH HO OH "OH OO-SIF

Convert the following chair conformation of the sugar a-D-galactose into a structure that shows all the cis & trans relationships as hashed (down) and wedge (up) bonds. HO 0 HO- CH₂OH ▾ HO OH . Use the wedge/hash bond tools to indicate stereochemistry where it exists. . In cases where there is more than one answer, just draw one. . Use "flat" representations of rings, not chairs, in your drawing. H₂C-O O OH HO OH "OH OO-SIF

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter12: Chirality

Section: Chapter Questions

Problem 15E

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Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure II and III are II: galactose, III: mannose II: mannose; III: galactose II and III are mannose II and III are galactose
Draw a formula for the lowest molecular weight compound that contains C, H, and possibly O, N or 5, is a chiral compound, contains ONLY one functional group, and is a sulfide. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include H atoms at chiral centers only. If a group is achiral, do not use wedged or hashed bonds on it. Alkene or alkyne groups are considered to be functional groups. 98 4 - /IP ChemDoodle
Convert the following chair conformation of the sugar beta-D-galactose into a structure that shows all the cis & trans relationships as hashed (down) and wedge (up) bonds. Use the wedge/hash bond tools to indicate stereochemistry where it exists. In cases where there is more than one answer, just draw one. Use “flat” representations of rings, not chairs, in your drawing.
1) Below you are given the structures of the disaccharides lactose and trehalose. он он но он но но OH но но OH но он но но OH Lactose Trehalose a. Identify clearly the hemiacetal and acetal groups in these disaccharides and determine for each of these identified groups if they have a- or B-configuration.
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Gentiobiose (D‑Glc(β1→6)D‑Glc) is a disaccharide found in some plant glycosides. Draw the Haworth structure of gentiobiose based on its abbreviated name. Show all multiatom groups using the groups tool. Show stereochemistry using wedge (upward) or dash (downward) bonds. The structures attached are not correct on Connect. Please consider a correct structure.
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Determine the open chain monosacchardie classification name (or not a sugar if no aldehyde, alcohol present); also determine whether the enantiomer is overall D, L, or Not an enaniomer to begin with? (note: technically the center carbon should be visible in the wedge-dash structure below...though im having problems changing it .just remember all carbons should be visible for a true wedge-dash structure) H. HO CHLOH open chain monosacchardie classification name: Aldotetrose Enantiomer tvpe: L
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chiral. If you were able to make another molecule that is a mirror image of the chiral molecule, the mirror image and the original molecule will be non-superimposable. i.e. the atoms surrounding carbon won't completely align. The lack of alignment of the suround atom makes the two molecules different from each other. The central carbon must be surrounded by 4 different groups. The chiral carbon is highlighted. CH;CH) CHICH2 CH3-C-CH2-CHy OH CH) miror The 3D structure of the above molecule focuses on the chiral carbon and the bond surrounding the chiral carbon. The molecule on the left is different from the molecule on the right (mirror image) because they are non-superimposable. H. CH3-C-COOH HOOC COOH CH NH2 NH2 mimor Answer the following questions: 1. Draw five structural isomers for hexane, CHe. Isomer 3 Isomer 2 Isomer 1 Isomer 5 Isomer 4 2. Draw three structural isomers as possible for CHO.
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