Convert the experimental glucose concentration (provided in the table below) from mM (millimolar) to g/100 mL.
Hints & Tips
- Take the 1/100 dilution factor into consideration
- Molarity will open the doors for you to get to grams.
- Once at M assume 1L of solution. (Hint: this will help you when converting from M to moles)
- You will also need to calculate the molar mass of glucose which has the formula C6H12O6
- There are 5 steps in total
Task 1: Write a step-by-step guide with key words for the Chem 2 students on how to do these calculations. You can use diagrams, a table or just type the steps out. Ensure the steps are clearly written and easy to follow.
|
Drink # |
Glucose Concentration in mM |
|
1 |
2.340 mM |
|
2 |
0.288 mM |
|
3 |
3.500 mM |
|
4 |
0.136 mM |
|
5 |
1.673 mM |
For each step show the corresponding calculation including equations where appropriate. You can choose any of the experimental results from the 5 drinks below to show your calculations.
- ONLY calculations for ONE drink are required.
- Remember to include the drink number you chose as a reference on your portfolio.
|
Drink # |
Glucose Concentration in mM |
|
1 |
2.340 mM |
|
2 |
0.288 mM |
|
3 |
3.500 mM |
|
4 |
0.136 mM |
|
5 |
1.673 mM |
*Provide your final answer with 2 decimal places.
Examples on how you could show your steps:
Step 1: convert from ….. to ……
X unit × Y = …… unit
Step 2: divide by …… to obtain …..
Show calculation for step 2 here
etc
|
Step 1: convert from … to …… |
Put calculation here |
|
Step 2: ……. |
Calculation |
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