Consider we have a stack that has the numbers 4, 1, 3 stored in that order. This means 4 is on top and 3 is at the bottom. How will our Stack look after the following lines of code are executed? Assume top is a reference to the node_t that represents the top of the stack.
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I want to make sure I got the beginning right :
3
1
4
then we would remove the 3 and the 1 since it's a pop
Stack looks like [1,2,1,7,3,1,3] (top to bottom)
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- Lab 18: Stack, SentenceReverser Java language Use a stack to reverse the words of a sentence. Keep reading words until you have a word that ends in a period, adding them onto a stack. When you have a word with a period, pop the words off and print them. Stop when there are no more words in the input. For example, you should turn the inputMary had a little lamb. Its fleece was white as snow.intoLamb little a had mary. Snow as white was fleece its.Pay attention to capitalization and the placement of the period.Create a program that loads the following elements in a stack. (Oppo, Realme, Samsung, Huawei, Vivo). Remove the last element in the stack and display the remaining elements. Show also the size of the stack and find the position of the element ‘Vivo’ in the stack.Try a spatuladef pancake_scramble(text):Analogous to flipping a stack of pancakes by sticking a spatula inside the stack and flipping over the stack of pancakes resting on top of that spatula, a pancake flip of order k performed for the text string reverses the prefix of first k characters and keeps the rest of the string as it were. For example, the pancake flip of order 2 performed on the string 'ilkka' would produce the string 'likka'. The pancake flip of order 3 performed on the same string would produce 'klika'.A pancake scramble, as defined in the excellent Wolfram Challenges programming problems site, consists of the sequence of pancake flips of order 2, 3, ... , n performed in this exact sequence for the given n-character text string. For example, the pancake scramble done to the string 'ilkka' would step through the intermediate results 'likka', 'kilka', 'klika' and 'akilk'. This function should compute and return the pancake scramble of its parameter text string. text…
- Lab 18: Stack, SentenceReverser Use a stack to reverse the words of a sentence. Keep reading words until you have a word that ends in a period, adding them onto a stack. When you have a word with a period, pop the words off and print them. Stop when there are no more words in the input. For example, you should turn the input Mary had a little lamb. Its fleece was white as snow. into Lamb little a had mary. Snow as white was fleece its. Pay attention to capitalization and the placement of the period.If you enqueue five elements into an empty queue and push the same elements in exactly the same order onto a stack, the elements on the queue from front to rear look the same as those on the stack from top to bottom. True FalseCheck out how well the stack does when it is allowed to operate in its natural state.
- data МАTH data ENGL null next next top top data MATH next null The above is a stack of textbooks. The top is a node to record the address of the top element of a stack. 2. Which of the following statement push the ENGL textbook to the top? top.next = new Node("ENGL", top); a. b. top = new Node("ENGL", top) Describe the reason of your choice. Your answer is (a or b) Will the push action take time in 0(1) or 0(n)? Next PageIf you enqueue five elements into an empty queue and push the same elements in exactly the same order onto a stack, the elements on the queue from front to rear look the same as those on the stack from top to bottom. True FalseGiven main.py, complete the Stack class in Stack.py by writing the push() and pop() methods. The stack uses an array of size 5 to store elements. The command Push followed by a positive number pushes the number onto the stack. The command Pop pops the top element from the stack. Entering -1 exits the program. Output "Can't push, stack is full" when push() is called on a full stack. Output "Can't pop, stack is empty" when pop() is called on an empty stack. Ex. If the input is: Push 1 Push 2 Push 3 Push 4 Push 5 Pop -1 Code given main.py(read-only) from Stack import Stack if __name__ == "__main__": stack = Stack(5) input_line = input() while input_line != '-1': split_input = input_line.split(' ') command = split_input[0] if command == 'Push': number_to_push = int(split_input[1]) stack.push(number_to_push) print('Stack contents (top to bottom):') stack.print_stack() elif command == "Pop":…
- input: 23+7* 26+9/ 14 2 + 160/ 99 2 + 50/24 - 100 4/3 * 20 + 143 *19 + 12/3+7* 23 7 + 10 * 14 + 19 - 22 * 16/ output: expression 23 +7* evaluates to 35 expression 2 6 + 9 / evaluates to 0 expression 14 2 + 160/ evaluates to 0 expression 99 2 + 50 / 24 - evaluates to -22 expression 100 4/3 * 20+ evaluates to 95 expression 14 3 * 19 + 12/3 + 7* evaluates to 56 expression 23 7 + 10 * 14 + 19 - 22 * 16/ evaluates to 405Java : Write the Java code segment that uses a stack to determine if a string is a palindrome (assume all that blanks have been removed). A palindrome contains the same characters forwards as backwards, for example level is a palindrome. Your solution must use only a stack, you MUST process the string from left to right, and are allowed to go through the string only once. You must use an efficient algorithm. Use : ArrayStack class given below: /** * Creates an empty stack using the default capacity. */ public ArrayStack() { this(DEFAULT_CAPACITY); } /** * Creates an empty stack using the specified capacity. * @param initialCapacity the initial size of the array */ public ArrayStack(int initialCapacity) { top = 0; stack = (T[])(new Object[initialCapacity]); }In Java, The following is a class definition of a linked list Node: class Node{int info;Node next;}Assume that head references a linked list and stores in order, the int values 5, 2 and 9. Show the instructions needed to move the value 2 in front of the value 5 so that the list is now 2, 5 and 9.