consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular pain company. suppose that a normal distribution with mean u= 6 ml and stand deviation of o=.2 ml is a reasonable model for a distribution of the variable x = amount of red dye in a paint mixture. use the normal distribution model to calculate the following probabilities.  p ( x<6.4) p (5.6 < x < 6.2)

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A: From the provided information, a) The mean can be calculated as:

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Q: Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint…

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Q: A random variable X has the following pdf: f(x) = 9xe-3"; x > 0

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Q: Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint…

A: As per guideline expert have to answer first three subpart only.

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A: Solution:

Q: Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint…

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Q: Suppose Z follows the standard normal distribution. Calculate the following probabilities using the…

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A: The total probability is equal to 1.

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Q: Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint…

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Q: A candy company claims that 32% of the jelly beans in its spring mix are pink. Suppose that the…

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A:

Q: The probability distribution of a discrete random variable x is shown in the following table: x 1 2…

A: E(X)=∑Xi P(X)E(X)=1×0.22+2×0.22+3×0.37+4×0.05+5×0.14E(X)=0.22+0.44+1.11+0.2+0.7E(X)=2.67

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A: Given : A normal distribution with mean μ = 4 ml and standard deviation σ = 0.2 ml   a) P(3.6 &lt; x…

Q: Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint…

A: X: amount of red dye in the paint mixtureX~N(μ,σ)where μ=6 ml , σ=0.2 ml

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A: Aa

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Q: For a normal distribution with a mean of µ = 500 and a standard deviation of σ = 25, find each of…

A: Given that, Mean = 500 Standard deviation = 25

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.