Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new [b[i] + b[i+1] for i in range(len(b)-1)] return foo(a-1, [1] + b_new + [1]) Fill-in the blank with the correct answer. The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is: T(a, n) = T ( +O(n %3D

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
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Python

Big-O Notation

Pls answer only if u know Big-O

Clue is given below:

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ΡΥTHOΝ
Big-o CODING/SOLVING
Consider the function below written in Python3:
def foo(a, b=[1]):
if a <= 1:
return b
b_new = [b[i] + b[i+1] for i in range(len(b)-1)]
return foo(a-1, [1] + b_new + [1])
Fill-in the blank with the correct answer.
The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is:
T(a, n) = T (|
) +o(n
CLUE/HINT: T(n-1) is NOT the answer.
Transcribed Image Text:ΡΥTHOΝ Big-o CODING/SOLVING Consider the function below written in Python3: def foo(a, b=[1]): if a <= 1: return b b_new = [b[i] + b[i+1] for i in range(len(b)-1)] return foo(a-1, [1] + b_new + [1]) Fill-in the blank with the correct answer. The recurrence relation for foo(a, b) when a > 0 and assuming n is the length of b is: T(a, n) = T (| ) +o(n CLUE/HINT: T(n-1) is NOT the answer.
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