Consider the following method for the analysis of cocaine (MW 303.35) powder. "Dissolve about 600 mg of cocaine, preciously dried and accurately weighed, in 50 mL of glacial acetic acid, add I drop of crystal violet TS, and titrate with 0.1 M perchloric acid VS to a green endpoint. Perform a blank determination, and make the necessary correction" Calculate the percentage purity of the cocaine sample from the data below. Show your reasoning clearly and record your final answer to four significant figures. • Cocaine powder weighed - 606.3 mg • Concentration of HCIO3 = 0.09978 M H₂C- Lo Volume HCIO; required for the assay mixture = 19.97 mL Volume HCIO; required for blank determination = 0.059 ml

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter31: Introduction To Analytical Separations
Section: Chapter Questions
Problem 31.19QAP
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Consider the following method for the analysis of cocaine (MW 303.35) powder.
"Dissolve about 600 mg of cocaine, preciously dried and accurately weighed, in 50 mL of
glacial acetic acid, add 1 drop of crystal violet TS, and titrate with 0.1 M perchloric acid VS
to a green endpoint. Perform a blank determination, and make the necessary correction"
Calculate the percentage purity of the cocaine sample from the data below. Show your
reasoning clearly and record your final answer to four significant figures.
Cocaine powder weighed = 606,3 mg
CH₂
Concentration of HCIO3 = 0.09978 M
H₂C-N
Volume HCIO3 required for the assay mixture = 19.97 mL
Volume HCIO, required for blank determination = 0.059 mL
Transcribed Image Text:Consider the following method for the analysis of cocaine (MW 303.35) powder. "Dissolve about 600 mg of cocaine, preciously dried and accurately weighed, in 50 mL of glacial acetic acid, add 1 drop of crystal violet TS, and titrate with 0.1 M perchloric acid VS to a green endpoint. Perform a blank determination, and make the necessary correction" Calculate the percentage purity of the cocaine sample from the data below. Show your reasoning clearly and record your final answer to four significant figures. Cocaine powder weighed = 606,3 mg CH₂ Concentration of HCIO3 = 0.09978 M H₂C-N Volume HCIO3 required for the assay mixture = 19.97 mL Volume HCIO, required for blank determination = 0.059 mL
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