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Consider the equilibrium system described by the chemical reaction below, which has a value of Kp equal to 4.7 × 101° at 200 K. If a flask is initially charged with 2.00 atm of H,S and 5.00 atm of O, what will the equilibrium partial pressure of SO, be? 2 H,S(g) + 3 0,(g) =2 H,0(g) + 2 SO,(9) 1 2 NEXT > Based on the given values, set ICE table in order to determine the unknown. 2 H,S(g) 3 0,(9) 2 H,O(g) 2 so,(g) Initial (atm) Change (atm) Equilibrium (atm) 5 RESET 2.00 5.00 +x +2x +3x -X -2x -3x 2.00 + x 2.00 + 2x 2.00 - x 2.00 - 2x 2.00 - 3x 5.00 + x 5.00 + 3x 5.00 - x 5.00 - 2x 5.00 - 3x

Consider the equilibrium system described by the chemical reaction below, which has a value of Kp equal to 4.7 × 101° at 200 K. If a flask is initially charged with 2.00 atm of H,S and 5.00 atm of O, what will the equilibrium partial pressure of SO, be? 2 H,S(g) + 3 0,(g) =2 H,0(g) + 2 SO,(9) 1 2 NEXT > Based on the given values, set ICE table in order to determine the unknown. 2 H,S(g) 3 0,(9) 2 H,O(g) 2 so,(g) Initial (atm) Change (atm) Equilibrium (atm) 5 RESET 2.00 5.00 +x +2x +3x -X -2x -3x 2.00 + x 2.00 + 2x 2.00 - x 2.00 - 2x 2.00 - 3x 5.00 + x 5.00 + 3x 5.00 - x 5.00 - 2x 5.00 - 3x

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 76AP: Methanol can be synthesized by means of the equilibriumreaction CO(g)+2H2(g)CH3OH(g) for which the...
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Please solve the third part which asks the following. 

Based on your ICE table and expression for Kp, solve for the partial pressure of SO2 at equillibrium.

Question 8 of 50 Submit Consider the equilibrium system described by the chemical reaction below, which has a value of Kp equal to 4.7 x 1010 at 200 K. If a flask is initially charged with 2.00 atm of H,S and 5.00 atm of O,, what will the equilibrium partial pressure of So, be? 7. 2 H,S(g) + 3 0,(9) =2 H,0(g) + 2 SO,(9) 1 2 3 NEXT > Based on the given values, set up ICE table in order to determine the unknown. 2 H,S(g) 3 0,(g) 2 H,O(g) 2 So,(g) + + Initial (atm) Change (atm) Equilibrium (atm) 5 RESET 2.00 5.00 +x +2x +3x -X -2x -3x 2.00 + x 2.00 + 2x 2.00 - 2.00 - 2x 2.00 - 3x 5.00 + x + 5.00 + 3x 5.00 - x 5.00 - 2x 5.00- Зх
Transcribed Image Text:Question 8 of 50 Submit Consider the equilibrium system described by the chemical reaction below, which has a value of Kp equal to 4.7 x 1010 at 200 K. If a flask is initially charged with 2.00 atm of H,S and 5.00 atm of O,, what will the equilibrium partial pressure of So, be? 7. 2 H,S(g) + 3 0,(9) =2 H,0(g) + 2 SO,(9) 1 2 3 NEXT > Based on the given values, set up ICE table in order to determine the unknown. 2 H,S(g) 3 0,(g) 2 H,O(g) 2 So,(g) + + Initial (atm) Change (atm) Equilibrium (atm) 5 RESET 2.00 5.00 +x +2x +3x -X -2x -3x 2.00 + x 2.00 + 2x 2.00 - 2.00 - 2x 2.00 - 3x 5.00 + x + 5.00 + 3x 5.00 - x 5.00 - 2x 5.00- Зх
Question 8 of 50 Submit Consider the equilibrium system described by the chemical reaction below, which has a value of Kp equal to 4.7 x 1010 at 200 K. If a flask is initially charged with 2.00 atm of H,S and 5.00 atm of O,, what will the equilibrium partial pressure of So, be? 7. 2 H,S(g) + 3 0,(g)= 2 H,O(g) + 2 so,(g) PREV 1 3 NEXT Based on your ICE table, set up the expression for Kp in order to determine the unknown. Do not combine or simplify terms. Kp = 4.7 x 1010 5 RESET (x) (x)² (2x) (2x)? (2.00 - x) (2.00 + x) (2.00 - x)? (2.00 + x)? (2.00 - 2x) (2.00 + 2x) (2.00 - 2x)? (2.00 + 2x)? (5.00 - x) (5.00 + x) (5.00 - x) (5.00 + x)3 (5.00 - 2x) (5.00 + 2x)? (5.00 - 3x) (5.00 + 3x) +
Transcribed Image Text:Question 8 of 50 Submit Consider the equilibrium system described by the chemical reaction below, which has a value of Kp equal to 4.7 x 1010 at 200 K. If a flask is initially charged with 2.00 atm of H,S and 5.00 atm of O,, what will the equilibrium partial pressure of So, be? 7. 2 H,S(g) + 3 0,(g)= 2 H,O(g) + 2 so,(g) PREV 1 3 NEXT Based on your ICE table, set up the expression for Kp in order to determine the unknown. Do not combine or simplify terms. Kp = 4.7 x 1010 5 RESET (x) (x)² (2x) (2x)? (2.00 - x) (2.00 + x) (2.00 - x)? (2.00 + x)? (2.00 - 2x) (2.00 + 2x) (2.00 - 2x)? (2.00 + 2x)? (5.00 - x) (5.00 + x) (5.00 - x) (5.00 + x)3 (5.00 - 2x) (5.00 + 2x)? (5.00 - 3x) (5.00 + 3x) +
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