Consider a single crystal oriented such that the slip direction and normal to the slip plane are at angles 42.7° and 48.3°, respectively, with the tensile axis. If the critical resolved shear stress is 26.3 MPa, what applied stress (in MPa) will be necessary to cause the single crystal to yield? i MPa

Consider a single crystal oriented such that the slip direction and normal to the slip plane are at angles 42.7° and 48.3°, respectively, with the tensile axis. If the critical resolved shear stress is 26.3 MPa, what applied stress (in MPa) will be necessary to cause the single crystal to yield? i MPa

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter9: Time, Temperature, And Mechanical Properties

Section: Chapter Questions

Problem 9.3P

See similar textbooks

Similar questions

Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 43.1° and 47.9°, respectively, with the tensile axis. If the critical resolved shear stress is 20.7 MPa, will an applied stress of 45 MPa cause the single crystal to yield or slip? If not, what stress will be necessary?
A single zinc crystal is loaded in tension with the normal to its slip plane at 60° to the tensile axis and the slip direction at 40° to the tensile axis. a) Calculate the resolved shear stress when a tensile stress of0.69 MPa is applied. b) What tensile stress is necessary to reach the critical resolved shear stress of 0.94 MPa?
A plate in equilibrium is subjected to uniform stresses along its edges with magnitude o = 30 %3D MPa and ow = 50 MPa as shown in the figure. %3D = 50 MPa %3D O = 30 MPa XX ple The Young's modulus of the material is 2 x 1011 N/m2 and the Poisson's ratio is 0.3. If o is negligibly small and assumed to be zero, then the strain Ezz is
At an axial load of 22 kN, a 15-mm-thick x 45-mm-wide polyimide polymer bar elongates 4.0 mm while the bar width contracts 0.15 mm. The bar is 260-mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine Poisson's ratio. O 0.175 O 0.217 O 0.297 0.235 O 0.280
A prismatic bar has a cross-section of 25 mm by 50 mm and a length of 2000 mm. Under an axial load of 100 kN, the measured elongation of the bar is 2mm. The tensile stress and % strain in the bar are
A prismatic bar has a cross-section of 25 mm x 50 mm and a length of 2000 mm. Under an axial load of 100 kN, the measured elongation of the bar is 2 mm. The tensile stress and % strain in the bar are?
a) plot how the critical stress intensity kc depends on the thickness and explain this?
A thin walled rotating shaft is subjected to a torque and a bending load. The torque produces the shear stress of 140 MPa. The bending load produces the normal stress varying through the shaft cross-section from -80 MPa to 80 MPa. The shaft may contain through cracks of unknown orientation with the length of up to 3.5 mm. The shaft material has oy-350 MPa, E= 70 GPa, v=0.315, KI-42 MPa-m¹2. The crack growth is approximately described by the Paris law with A=6.9-10-12 (m/cycle)/[(MPa-m¹²)³]. Assume that K₁=1.1.0 √√a, where a is the crack half length. Estimate the number of revolutions that can be withstood without failure.
At a point in a strained material, tensile stress of 100 MPa and compressive stress of 60 MPa are found to be principal stresses Maximum shear stress at that point is: O 60 MPa O 20 MPa O 40 MPa O 80 MPa
At a point in elastic medium normal stresses in two mutually perpendicular directions are 120 MPa, 40 MPa (both tensile) associated with a tangential stress of 30 MPa. The principal stresses at the locations are
Q.3. (30%) A circular aluminum tube subjected to T pure torsion by torques T has an outer radius r2 equal to 2 times the inner radius r1. (a) If the maximum shear strain in the tube is measured as 500x10-6 rad, what is the shear strain y1 at the inner surface? (b) If the maximum allowable rate of twist (0) is 0.15°/m and the maximum shear strain is to be kept at 500x10-6 rad by adjusting the torque T, what is the minimum required outer radius (r2 )min?
Which of the following is correct regarding the principal stress and maximum in-plane shear stress? a) The shear stress over principal stress planes is zero, b) The maximum in-plane shear stress is always smaller than the principal stresses, c) A principal stress plane can be reached by rotating the maximum in-plane shear stress plane 90 degrees in the clockwise direction, d) Principal stress can not be negative.