Consider a point in a structural member that is subjected to plane stress. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are S= 12 ksi, S,= 18 ksi, and Sy 13 ksi. (a) Determine the principal stresses (1 > o) and the maximum in-plane shear stress rmax acting at the point. (D) Find the smallest rotation angle 6, (counterclockwise is positive, clockwise is negative) that will rotate to principal directions. Then show these stresses in an appropriate sketch (e.g, see Figure 12.15 or Figure 12.16) Answers ksi. ksi. max = ksi. e, = i

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
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Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.4.19P: -18 through 7.4-25 An clement in plane stress is subjected to stresses sx,??y, and r. (see figure)....
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Consider a point in a structural member that is subjected to plane stress. Normal and shear stress magnitudes acting on horizontal and
vertical planes at the point are S = 12 ksi, S = 18 ksi, and Sy= 13 ksi.
(a) Determine the principal stresses (1 > o) and the maximum in-plane shear stress rmaxr acting at the point.
(b) Find the smallest rotation angle 8, (counterclockwise is positive, clockwise is negative) that will rotate to principal directions. Then
show these stresses in an appropriate sketch (eg, see Figure 12.15 or Figure 12.16)
Answers
Opl =
ksi.
ksi.
max =
ksi.
e, =
Transcribed Image Text:Consider a point in a structural member that is subjected to plane stress. Normal and shear stress magnitudes acting on horizontal and vertical planes at the point are S = 12 ksi, S = 18 ksi, and Sy= 13 ksi. (a) Determine the principal stresses (1 > o) and the maximum in-plane shear stress rmaxr acting at the point. (b) Find the smallest rotation angle 8, (counterclockwise is positive, clockwise is negative) that will rotate to principal directions. Then show these stresses in an appropriate sketch (eg, see Figure 12.15 or Figure 12.16) Answers Opl = ksi. ksi. max = ksi. e, =
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