code1 code2 if (a_in=0 or b_in=0) then { r=0; } else { a=a_in; n=b_in; r=0; } while (n !=0 ) { r=r+a; n=n-1; } } r_out =r; if (a_in=0 b_in_0) then { r=0; } else { a = a_in; n = b_in; r = 0; op: r= r + a; n = n - 1; if ( n = 0) then { goto stop; }
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Which one do you consider more efficient? Why?
code1 |
code2 |
if (a_in=0 or b_in=0) then { r=0; } else { a=a_in; n=b_in; r=0; } while (n !=0 ) { r=r+a; n=n-1; } } r_out =r;
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if (a_in=0 b_in_0) then { r=0; } else { a = a_in; n = b_in; r = 0; op: r= r + a; n = n - 1; if ( n = 0) then { goto stop; } else { goto op; } } stop : r_out = r ;
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- while (*psz_2 != 0) {;u8_c = *psz_2;;if (u8_c > 0x2F) {;*psz_1 = u8_c | 0x20;;} else {;*psz_1 = u8_c;;}Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxCFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
- PYTHON PROGRAMMING Reza Enterprises sells tickets for buses, tours, and other travel services. Because Reza frequently mistypes long ticket numbers, Reza Enterprises has asked his students to write an application that shows if a ticket is invalid. Your application/program tells the ticket agent to enter a six-digit ticket number. Ticket numbers are designed so that if you lose the last digit of the number, then divide by 7, the remainder of the division is exactly the same to the last dropped digit. This process is shown below: Step 1: Enter the ticket number; for example 123454 Step 2: Remove the last digit, leaving 12345 Step 3: Determine the remainder when the ticket number from step 2 is divided by 7. In this case, 12345 divided by 7 leaves a remainder of 4. Step 4: Display a message to the ticket agent indicating whether the ticket number is valid or not. If the ticket number is valid, save the number to a .txt file called “tickets.txt” and continue to loop your program…K Lold T T=T+(K-2)*L T=T- 10 T=0 T=T-10 K= 4, 8, 2 L=4, 3, -1 T=T+{K-2)*LPython Knapsack: you are carrying a knapsack with capacity to hold a total of weight C. You are selecting among n items with values A={a1, a2, ... , an} and associated weights W={w1, w2, ... , wn}. Here the weights and values are all positive. You wish to maximize the total value of the items you select not exceeding the given weight capacity, example, maximize sum_{a in A} such that sum_{w in W} <= C. Note that you can only select your items once. In Python, create function DP_K (C, A, W) as stated above. Input an array to the function to hold the backtrace. What is the best set of items for C = 30, A = [40, 110, 100] and w = [20, 30, 40]? This can be shown using auxiliary printing function.
- double tab1[5] = {2,3,4,5,6}; double tab2[5] = {6,5,4,3,2}; for(int i = 0;i<5;i++) { tab1[i] = tab1[i]*tab2[i]; cout<<tab1[i]<<" "; } 12 15 16 15 16 15 15 16 15 12 12 15 16 15 12 12 15 12 15 12#include<iostream>using namespace std;void main(){double pi = 0, denominator = 1;int counter = 999999;for (int x = 0; x < counter; x++){if (x % 2 != 0){pi = pi - (1 / denominator);}else{pi = pi + (1 / denominator);}denominator = denominator + 2;}pi = pi * 4;cout << " So the computed value of a PI is = " << pi << endl;cout << " ";//return 0;system("pause");} Note: This a program called ComputePI to compute the value of π Tutor just have to Modify This program to use nested-if (if ... else if ... else if ... else) instead. Explain by applying a double line commentJava Program 01 - Theater Ticket System A small ten-seat theater has contracted you to build software which will reserve tickets. The theater has two rows of five seats each. Each row is referred to by number (1 or 2) and each seat in the row is referred to by letter (A, B, C, D, and E). When started, the program should ask the user for the row they prefer (row selection). If that row has no empty seats then the program should ask the user if they prefer the other row, if no then display a message stating the next show is tomorrow. Upon selecting a row, the program should present the user with a choice of available seats in the row. The user can then either choose a seat and print the ticket (in this case a simple message will suffice) or return to row selection. If a ticket is printed the program should return to row selection. The program terminates when all seats are reserved. Please enter a row: 1 Available seats: A B C D E Which seat, enter Q for none?: B You have…
- -0 FAMAS oro ag -0 1 void printVerticalGraph(int nUnits) { 2 4 9 10 11 12 13 14 15 16 17 456 BARHEIDEN 18 19 20 21 22 23 24 25 26 27 int nRev; printf("%d\n", nUnits); while (nUnits>0){ nRev = getReverse (nUnits); // 1) Adjust nUnits ?? [Q1] ?? while (nRev>0){ nUnits *= 10; // 2) Condition to print * if(?? [Q2]??) { printf("*"); } // 3) Update for nUnits for * case ?? [Q3] ?? }else{ printf(" "); // 4) Update for nUnits for ?? [Q4]?? } // 5) Update to nRev ?? [Q5]?? printf("\n"); caseSum of two squares def sum_of_two_squares(n): Some positive integers can be expressed as a sum of two squares of some positive integers greater than zero. For example, 74 = 49 + 25 = 72 + 52. This function should find and return a tuple of two positive integers whose squares together add up to n, or return None if the parameter n cannot be broken into a sum of two squares.To facilitate the automated testing, the returned tuple must present the larger of its two numbers first. Furthermore, if some integer can be broken down to a sum of squares in several ways, return the breakdown that maximizes the larger number. For example, the number 85 allows two such representations 72 + 62 and 92 + 22 , of which this function must return (9, 2).The technique of two approaching indices that start from the beginning and end of a sequence, respectively, and approach each other until they meet somewhere, used in the function two_summers in one of our class examples, is directly applicable to this…Sum of two squares def sum_of_two_squares(n): Some positive integers can be expressed as a sum of two squares of some positive integers greater than zero. For example, 74 = 49 + 25 = 72 + 52. This function should find and return a tuple of two positive integers whose squares together add up to n, or return None if the parameter n cannot be broken into a sum of two squares. To facilitate the automated testing, the returned tuple must present the larger of its two numbers first. Furthermore, if some integer can be broken down to a sum of squares in several ways, return the breakdown that maximizes the larger number. For example, the number 85 allows two such representations 72 + 62 and 92 + 22 , of which this function must return (9, 2). The technique of two approaching indices that start from the beginning and end of a sequence, respectively, and approach each other until they meet somewhere, used in the function two_summers in one of our class examples, is directly applicable to this…